The normal to the curve x² = 4y at the point (2, 1) is:
The normal to the curve x² = 4y at the point (2, 1) is:
- A. x + y = 3
- B. x - y = 1
- C. x + 2y = 4
- D. 2x - y = 3
Answer: A) x + y = 3
Explanation: Differentiating x² = 4y yields 2x = 4(dy/dx), so dy/dx = x/2. At (2,1), tangent slope = 1. Normal slope = -1. Equation: y - 1 = -1(x - 2) → x + y = 3.
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