The equation of the tangent to the curve y = x³ - 3x + 2 at the point where it crosses the y-axis is:
The equation of the tangent to the curve y = x³ - 3x + 2 at the point where it crosses the y-axis is:
- A. 3x - y = 0
- B. x + 3y - 2 = 0
- C. x - 3y = 0
- D. 3x + y - 2 = 0
Answer: D) 3x + y - 2 = 0
Explanation: It crosses y-axis at x = 0, giving y = 2. Point is (0, 2). dy/dx = 3x² - 3. At x = 0, m = -3. Equation of tangent: y - 2 = -3(x - 0), which is 3x + y - 2 = 0.
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