If f(x) = { x², x is rational; 0, x is irrational }, then f is continuous at: A. x = 0 only B. all points C. x = 1 D. nowhere Answer: A) x = 0 only Explanation: For x ≠ 0, limit does not exist because values oscillate. At x = 0, |f(x)| ≤ x² → limit 0 = f(0). So continuous at 0 only.

imo class 12 continuity and differentiability

If f(x) = { x², x is rational; 0, x is irrational }, then f is continuous at:

VAVidaara Admin Asked 6d ago 0 views 0 answers

If f(x) = { x², x is rational; 0, x is irrational }, then f is continuous at:

Answer: A) x = 0 only

Explanation: For x ≠ 0, limit does not exist because values oscillate. At x = 0, |f(x)| ≤ x² → limit 0 = f(0). So continuous at 0 only.