Evaluate the limit as a sum: lim n→∞ (1/(n+1) + 1/(n+2) + ... + 1/(2n)).
Evaluate the limit as a sum: lim n→∞ (1/(n+1) + 1/(n+2) + ... + 1/(2n)).
- A. 1
- B. ln 2
- C. e
- D. 0
Answer: B) ln 2
Explanation: Rewriting as lim (1/n) Σ [1 / (1 + r/n)] from r=1 to n. This converts to ∫[0 to 1] 1/(1+x) dx = [ln(1+x)] from 0 to 1 = ln 2.
0 Answers
Log in to post your own answer or join the discussion.
No comments yet — start the discussion.