Evaluate ∫₁ᵉ (1 + log x) dx.
Evaluate ∫₁ᵉ (1 + log x) dx.
- A. e
- B. e + 1
- C. e − 1
- D. 1
Answer: A) e
Explanation: ∫₁ᵉ (1 + log x) dx = [x + x log x − x]₁ᵉ? Actually, ∫ log x dx = x log x − x. So ∫(1+log x)dx = x + x log x − x = x log x. From 1 to e: e log e − 1 log 1 = e − 0 = e.
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