Evaluate ∫₀^(π/4) tan² x dx.
Evaluate ∫₀^(π/4) tan² x dx.
- A. 1 − π/4
- B. π/4 − 1
- C. π/4
- D. 1
Answer: A) 1 − π/4
Explanation: tan² x = sec² x − 1. ∫₀^(π/4) (sec² x − 1) dx = [tan x − x]₀^(π/4) = (1 − π/4) − 0 = 1 − π/4.
0 Answers
Log in to post your own answer or join the discussion.
No comments yet — start the discussion.