imo class 12 definite integration

Find the value of ∫[0 to 1] x(1 - x)⁹⁹ dx.

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Find the value of ∫[0 to 1] x(1 - x)⁹⁹ dx.

  • A. 1/10100
  • B. 1/9900
  • C. 1/100
  • D. 1/10000

Answer: A) 1/10100

Explanation: Using property ∫[0 to 1] f(x) dx = ∫[0 to 1] f(1-x) dx, the integral becomes ∫[0 to 1] (1-x)x⁹⁹ dx = ∫(x⁹⁹ - x¹⁰⁰) dx = [x¹⁰⁰/100 - x¹⁰¹/101] from 0 to 1 = 1/100 - 1/101 = 1/10100.

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