If |a a² 1+a³; b b² 1+b³; c c² 1+c³| = 0 and a, b, c are distinct, then abc equals:
If |a a² 1+a³; b b² 1+b³; c c² 1+c³| = 0 and a, b, c are distinct, then abc equals:
- A. 0
- B. 1
- C. −1
- D. 2
Answer: C) −1
Explanation: Split determinant: |a a² 1| + |a a² a³|. Second det = abc |1 a a²; 1 b b²; 1 c c²|. First det = (a−b)(b−c)(c−a). Sum = 0 leads to abc = −1.
0 Answers
Log in to post your own answer or join the discussion.
No comments yet — start the discussion.