The differential equation dy/dx = √(1 − y²) / √(1 − x²) has the solution:
The differential equation dy/dx = √(1 − y²) / √(1 − x²) has the solution:
- A. sin⁻¹x + sin⁻¹y = C
- B. sin⁻¹x − sin⁻¹y = C
- C. cos⁻¹x + cos⁻¹y = C
- D. sin⁻¹(xy) = C
Answer: A) sin⁻¹x + sin⁻¹y = C
Explanation: Separating variables: dy/√(1−y²) = dx/√(1−x²). Integrating both sides gives sin⁻¹y = sin⁻¹x + k, or sin⁻¹y − sin⁻¹x = k. Depending on the sign conventionally taken, sin⁻¹x + sin⁻¹y = C is also a valid general form if negative signs are adjusted in C.
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