Form the differential equation for the family of curves y = A e^(3x) + B e^(−3x).
Form the differential equation for the family of curves y = A e^(3x) + B e^(−3x).
- A. d²y/dx² + 9y = 0
- B. d²y/dx² − 9y = 0
- C. d²y/dx² + 3y = 0
- D. d²y/dx² − 3y = 0
Answer: B) d²y/dx² − 9y = 0
Explanation: y' = 3A e^(3x) − 3B e^(−3x). y'' = 9A e^(3x) + 9B e^(−3x) = 9(A e^(3x) + B e^(−3x)) = 9y. Hence, d²y/dx² − 9y = 0.
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