The integrating factor of the differential equation x log x (dy/dx) + y = 2/x is:
The integrating factor of the differential equation x log x (dy/dx) + y = 2/x is:
- A. log x
- B. x
- C. eˣ
- D. 1/x
Answer: A) log x
Explanation: Divide by x log x: dy/dx + y/(x log x) = 2/(x² log x). P = 1/(x log x). IF = e^(∫dx/(x log x)). Let log x = t, then (1/x)dx = dt. IF = e^(∫dt/t) = e^(log t) = t = log x.
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