Evaluate: ∫ eˣ / (1 + eˣ) dx
Evaluate: ∫ eˣ / (1 + eˣ) dx
- A. log|1 + eˣ| + C
- B. eˣ + x + C
- C. log|eˣ| + C
- D. 1 / (1 + eˣ) + C
Answer: A) log|1 + eˣ| + C
Explanation: Let 1 + eˣ = t, then eˣ dx = dt. Integral becomes ∫ 1/t dt = log|t| + C = log|1 + eˣ| + C.
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