Find ∫ (1/x) log(log x) dx
Find ∫ (1/x) log(log x) dx
- A. (log x) [log(log x) - 1] + C
- B. (log(log x))² / 2 + C
- C. log|log x| + C
- D. log x log(log x) + C
Answer: A) (log x) [log(log x) - 1] + C
Explanation: Let log x = t, (1/x)dx = dt. ∫ log t dt. By parts, t log t - t + C = log x [log(log x) - 1] + C.
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