Evaluate: ∫ (sin⁻¹ x)² / √(1 - x²) dx
Evaluate: ∫ (sin⁻¹ x)² / √(1 - x²) dx
- A. (sin⁻¹ x)³ / 3 + C
- B. 2(sin⁻¹ x) + C
- C. (sin⁻¹ x)² / 2 + C
- D. - (cos⁻¹ x)³ / 3 + C
Answer: A) (sin⁻¹ x)³ / 3 + C
Explanation: Let sin⁻¹ x = t, then 1/√(1 - x²) dx = dt. ∫ t² dt = t³/3 + C = (sin⁻¹ x)³ / 3 + C.
0 Answers
Log in to post your own answer or join the discussion.
No comments yet — start the discussion.