Evaluate: ∫ (log x) / x dx
Evaluate: ∫ (log x) / x dx
- A. log(log x) + C
- B. (log x)² / 2 + C
- C. 1/x² + C
- D. x log x + C
Answer: B) (log x)² / 2 + C
Explanation: Let log x = t, then (1/x) dx = dt. The integral becomes ∫ t dt = t²/2 + C = (log x)² / 2 + C.
0 Answers
Log in to post your own answer or join the discussion.
No comments yet — start the discussion.