Evaluate: ∫ (eˣ (1 + x log x) / x) dx
Evaluate: ∫ (eˣ (1 + x log x) / x) dx
- A. eˣ log x + C
- B. eˣ / x + C
- C. eˣ (log x + x) + C
- D. eˣ log|x| + eˣ + C
Answer: A) eˣ log x + C
Explanation: Rewriting as ∫ eˣ (1/x + log x) dx. This matches ∫ eˣ (f'(x) + f(x)) dx where f(x) = log x. Result is eˣ f(x) = eˣ log x + C.
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