∫x sec²x dx equals:
∫x sec²x dx equals:
- A. x tan x − ln|sec x| + C
- B. x tan x + ln|cos x| + C
- C. tan x + C
- D. x sec x tan x + C
Answer: B) x tan x + ln|cos x| + C
Explanation: u = x, dv = sec²x dx. du = dx, v = tan x. ∫ = x tan x − ∫tan x dx = x tan x − (−ln|cos x|) + C = x tan x + ln|cos x| + C.
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