If tan⁻¹(x) + tan⁻¹(y) + tan⁻¹(z) = π, then x + y + z equals:
If tan⁻¹(x) + tan⁻¹(y) + tan⁻¹(z) = π, then x + y + z equals:
- A. 0
- B. 1
- C. xyz
- D. x+y+z
Answer: C) xyz
Explanation: tan(A+B+C) = (Sum(tan A) − Product(tan A)) / (1 − Sum(tan A tan B)). If A+B+C = π, tan(π) = 0. So the numerator is 0, meaning Sum(tan A) = Product(tan A). Thus x+y+z = xyz.
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