[JEE Main 2005] in triangle pqr angle r pi 2 if tan p2 and tan q2 are
In $\triangle PQR$, $\angle R=\frac\pi2$. If $\tan\frac P2$ and $\tan\frac Q2$ are the roots of $ax^2+bx+c=0$ ($a\ne0$), then
(a) $a=b+c$
(b) $c=a+b$
(c) $b=c$
(d) $b=a+c$
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 2d ago
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Correct answer: (b) $c=a+b$
$\frac P2+\frac Q2=\frac\pi4$, so $\tan\frac P2+\tan\frac Q2=1-\tan\frac P2\tan\frac Q2$, i.e. $-\frac ba=1-\frac ca\Rightarrow c=a+b$.
JEE Main 2005 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.
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