[JEE Advanced 1998] The number of divisors of the form $4n+2$ ($n\ge0$) of the integer $240$ is
The number of divisors of the form $4n+2$ ($n\ge0$) of the integer $240$ is
(a) $4$
(b) $8$
(c) $10$
(d) $3$
1 Answer
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✓ Vidaara Team
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· 1mo ago
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Correct answer: (a) $4$
$240=2^4\cdot3\cdot5$; divisors $\equiv2\pmod4$ are $2\times(\text{odd divisor of }15)$: $2,6,10,30$ — four of them.
JEE Advanced 1998 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.
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