[JEE Advanced 2002] the set of all real x for which x 2 x 2 x 0
The set of all real $x$ for which $x^2-|x+2|+x>0$ is
(a) $(-\infty,-2)\cup(2,\infty)$
(b) $(-\infty,-\sqrt2)\cup(\sqrt2,\infty)$
(c) $(-\infty,-1)\cup(1,\infty)$
(d) $(\sqrt2,\infty)$
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 2d ago
▲ 0
Correct answer: (b) $(-\infty,-\sqrt2)\cup(\sqrt2,\infty)$
For $x\ge-2$: $x^2-2>0\Rightarrow x<-\sqrt2$ or $x>\sqrt2$; for $x<-2$: $(x+1)^2+1>0$ always. Union $=(-\infty,-\sqrt2)\cup(\sqrt2,\infty)$.
JEE Advanced 2002 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.
Log in to post your own answer or join the discussion.
No comments yet — start the discussion.