Let y = ( x),x > 1 therefore, dx = dx ( x) = ( x) dx ( x) = x x = x x ,x > 1

Continuity and Differentiability — Class 12 Maths Solution

ncert exercise SA NCERT Ex.5.4 ,Q.8,Page 174

Question

$\log (\log x),x > 1$

Step-by-step Solution

Let y $=$ $\log (\log x),x > 1$

therefore, $\cfrac{{dy}}{{dx}} = \cfrac{d}{{dx}}\log (\log x) = \cfrac{1}{{(\log x)}} \cdot \cfrac{d}{{dx}}(\log x)$

$= \cfrac{1}{{\log x}} \cdot \cfrac{1}{x} = \cfrac{1}{{x\log x}},x > 1$

NCERT & Exemplar solution for CBSE Class 12 Mathematics, Continuity and Differentiability. Curated by Sachin Sharma. Free for all students.