Inverse Trigonometric Functions — Class 12 Maths Solution

exemplar objective MCQ NCERT,Ex.2.3,Q.30,Page.38
Question

If ${\tan ^{ - 1}}x + {\tan ^{ - 1}}y = \frac{{4\pi }}{5}$, then ${\cot ^{ - 1}}x + {\cot ^{ - 1}}y$ equals to

  • (a) $\frac{\pi }{5}$ ✓ Correct
  • (b) $\frac{{2\pi }}{5}$
  • (c) $\frac{{3\pi }}{5}$
  • (d) $\pi$
Step-by-step Solution
Correct answer: option (a)

We have, ${\tan ^{ - 1}}x + {\tan ^{ - 1}}y = \frac{{4\pi }}{5}$

$\Rightarrow$ $\frac{\pi }{2} - {\cot ^{ - 1}}x + \frac{\pi }{2} - {\cot ^{ - 1}}y = \frac{{4\pi }}{5}$

$\Rightarrow$ $- \left( {{{\cot }^{ - 1}}x + {{\cot }^{ - 1}}y} \right) = \frac{{4\pi }}{5} - \pi$

$\Rightarrow$ ${\cot ^{ - 1}}x + {\cot ^{ - 1}}y = - \left( { - \frac{\pi }{5}} \right)$

$\Rightarrow$ ${\cot ^{ - 1}}x + {\cot ^{ - 1}}y = \frac{\pi }{5}$

NCERT & Exemplar solution for CBSE Class 12 Mathematics, Inverse Trigonometric Functions. Curated by Sachin Sharma. Free for all students.