( 3 - - 1 ( - 2 ) ) is equal to (A) 2 (B) 3 (C) 4 (D) 1

Option D is correct ( 3 - - 1 ( - 2 ) ) = ( 3 + - 1 ( 2 ) ) = ( 3 + 6 ) = 2 = 1

Inverse Trigonometric Functions — Class 12 Maths Solution

ncert exercise SA NCERT Ex. 2.2, Q. 20 , Page 48

Question

$\sin \left( {\frac{\pi }{3} - {{\sin }^{ - 1}}\left( { - \frac{1}{2}} \right)} \right)$ is equal to

(A) $\frac{1}{2}$

(B) $\frac{1}{3}$

(D) 1

Step-by-step Solution

Option D is correct

$\sin \left( {\frac{\pi }{3} - {{\sin }^{ - 1}}\left( { - \frac{1}{2}} \right)} \right) = \sin \left( {\frac{\pi }{3} + {{\sin }^{ - 1}}\left( {\frac{1}{2}} \right)} \right)$

$= \sin \left( {\frac{\pi }{3} + \frac{\pi }{6}} \right) = \sin \frac{\pi }{2} = 1$

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NCERT & Exemplar solution for CBSE Class 12 Mathematics, Inverse Trigonometric Functions. Curated by Sachin Sharma. Free for all students.