- 1 3 - - 1 ( - 3 ) is equal to (A) (B) - 2 (C) 0 (D) 2 3

Option B is correct - 1 3 - - 1 ( - 3 ) = - 1 3 - ( - - 1 3 ) = - 1 3 - + - 1 3 = 3 - + 6 = 2 - = - 2 . [couleur = blue!30, arrondi = 0.1 ] Miscellaneous Exercise Find the value of the following : ;

Inverse Trigonometric Functions — Class 12 Maths Solution

ncert exercise SA NCERT Ex. 2.2, Q.21 , Page 48

Question

${\tan ^{ - 1}}\sqrt 3 - {\cot ^{ - 1}}( - \sqrt 3 )$ is equal to

(A) $\pi$

(B) $- \frac{\pi }{2}$

(D) $2\sqrt 3$

Step-by-step Solution

Option B is correct

${\tan ^{ - 1}}\sqrt 3 - {\cot ^{ - 1}}( - \sqrt 3 ) = {\tan ^{ - 1}}\sqrt 3 - (\pi - {\cot ^{ - 1}}\sqrt 3 )$

$= {\tan ^{ - 1}}\sqrt 3 - \pi + {\cot ^{ - 1}}\sqrt 3 = \frac{\pi }{3} - \pi + \frac{\pi }{6} = \frac{\pi }{2} - \pi = - \frac{\pi }{2}.$

$figure$

← All Inverse Trigonometric Functions solutions Practice tests →

NCERT & Exemplar solution for CBSE Class 12 Mathematics, Inverse Trigonometric Functions. Curated by Sachin Sharma. Free for all students.