AP Calculus AB

Contextual Applications of Differentiation

AP Calculus AB — Unit 4

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Module 1

Foundations & Definitions

Overview, Objectives & Key DefinitionsTopic 1

Unit Overview

Having learned how to differentiate, this unit is about what derivatives mean in the real world. A derivative is a rate of change, and interpreting it correctly — with units and direction — is a core AP skill. You will study motion (position, velocity, acceleration), related rates (how linked quantities change together in time), linearization (using a tangent line to approximate), and L'Hôpital's Rule (using derivatives to resolve indeterminate limits).

This unit is heavy on interpretation and problem set-up. On the exam it is a frequent source of free-response questions.

Big picture: A derivative carries units of output per unit of input and tells you both how fast and which direction a quantity is changing.


Learning Objectives

  • Interpret a derivative's value, sign, and units in context.
  • Analyze rectilinear motion: relate position, velocity, acceleration, speed, and displacement.
  • Set up and solve related-rates problems.
  • Use local linearity / linearization to approximate function values.
  • Apply L'Hôpital's Rule to indeterminate forms 0/0 and ∞/∞.

Prerequisite Concepts

  • Fluent differentiation, especially the Chain Rule (Unit 3) — essential for related rates.
  • Geometry formulas (area, volume, Pythagoras, similar triangles).
  • Indeterminate forms from Unit 1.

Key Definitions

  • Rate of change in context: f'(a) has units of (units of f) per (unit of x); its sign tells direction (increasing/decreasing).
  • Velocity: v(t) = s'(t). Acceleration: a(t) = v'(t) = s''(t). Speed: |v(t)|.
  • Displacement: net change in position. At rest: v(t) = 0.
  • Related rates: quantities linked by an equation, each changing with time; differentiate the relation with respect to t.
  • Linearization of f at a: L(x) = f(a) + f'(a)(x − a) (the tangent-line approximation).
  • Indeterminate form: an expression like 0/0 or ∞/∞ whose value is not determined by the parts alone.

✎ Self-Check — 5 questions0 / 5
Q1.The volume of water in a tank is V(t) liters after t minutes. What are the units of V'(t)?
Explanation: A derivative has units of (units of output) per (unit of input): liters per minute.
Q2.A cup of coffee cools so that its temperature is T(t) degrees Celsius after t minutes. T'(5) = -2 means:
Explanation: A negative derivative means the quantity is decreasing; T'(5) = -2 means the temperature is falling at 2 C per minute at t = 5.
Q3.The height of a plant is h(t) cm after t days. h'(t) represents:
Explanation: h'(t) is the instantaneous rate of change of height with respect to time, i.e., the growth rate in cm/day.
Q4.A particle moves with position s(t) = t^2 - 4t. What is its velocity function v(t)?
Explanation: Velocity is the derivative of position: v(t) = s'(t) = 2t - 4.
Q5.If v(t) is velocity, what is the acceleration a(t)?
Explanation: Acceleration is the derivative of velocity: a(t) = v'(t) = s''(t).
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Module 2

Theorems & Formulas

Important Theorems & FormulasTopic 1

Important Theorems / Rules

L'Hôpital's Rule: If lim f/g gives 0/0 or ∞/∞ and the limits of f' and g' behave, then lim f(x)/g(x) = lim f'(x)/g'(x). Check the indeterminate form before applying; a form like 1/0 is not indeterminate.

Speeding up / slowing down: a particle is speeding up when v and a have the same sign, and slowing down when they have opposite signs.


Important Theorems / Rules

L'Hôpital's Rule: If lim f/g gives 0/0 or ∞/∞ and the limits of f' and g' behave, then lim f(x)/g(x) = lim f'(x)/g'(x). Check the indeterminate form before applying; a form like 1/0 is not indeterminate.

Speeding up / slowing down: a particle is speeding up when v and a have the same sign, and slowing down when they have opposite signs.


Important Formulas

  • Linearization: L(x) = f(a) + f'(a)(x − a); differential dy = f'(x) dx.
  • Common related-rates relations (differentiate w.r.t. t):
    • Circle area A = πr²dA/dt = 2πr (dr/dt)
    • Sphere volume V = (4/3)πr³dV/dt = 4πr² (dr/dt)
    • Cube volume V = s³dV/dt = 3s² (ds/dt)
    • Right-triangle / Pythagoras x² + y² = z²2x(dx/dt) + 2y(dy/dt) = 2z(dz/dt)

✎ Self-Check — 5 questions0 / 5
Q1.If C(x) is the cost in dollars to produce x items, what does C'(200) = 3 mean?
Explanation: C'(x) is the marginal cost, the approximate cost of producing one additional item. C'(200) = 3 means the cost is rising by about $3 per item at x = 200.
Q2.A population P(t) satisfies P(10) = 5000 and P'(10) = 120. Approximately what is P(11)?
Explanation: Using the local linear approximation, P(11) ≈ P(10) + P'(10)(1) = 5000 + 120 = 5120.
Q3.If f'(a) > 0 at a point a, what can be concluded about f near a?
Explanation: A positive derivative indicates that the function is increasing at that point.
Q4.The number of bacteria is N(t) after t hours. If N'(3) = 400, the units are:
Explanation: The derivative measures how fast the count changes with time: bacteria per hour.
Q5.A particle has position s(t) = t^2 - 4t. At what time t is the particle at rest?
Explanation: The particle is at rest when v(t) = 2t - 4 = 0, which gives t = 2.
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Module 3

Concepts & Worked Examples

Concept Explanations & Solved ExamplesTopic 1

Concept Explanations

Interpreting derivatives (4.1). Always attach units and read the sign. If T(t) is temperature in °C after t minutes, then T'(5) = −2 means "cooling at 2 °C per minute at t = 5." A second derivative describes how the rate itself is changing (e.g., increasing at a decreasing rate).

Motion (4.2). Differentiate position to get velocity, again to get acceleration. Watch the distinction between displacement (integral/net of velocity, can be negative) and total distance (accounts for turnarounds where v = 0). Use the same-sign rule to decide speeding up vs. slowing down.

Related rates (4.4–4.5) — the standard method:

  1. Draw and label; identify which rates are given and which is wanted.
  2. Write an equation relating the variables (geometry).
  3. Differentiate both sides with respect to t (Chain Rule everywhere).
  4. Substitute the known instantaneous values last — never before differentiating.
  5. Solve for the unknown rate; include units.

Linearization (4.6). Near x = a, a smooth curve looks like its tangent line. Use L(x) to approximate hard values (e.g., √4.1 ≈ 2.025). For a concave-up function the tangent lies below the curve, so the estimate is an underestimate; concave-down gives an overestimate.

L'Hôpital's Rule (4.7). When substitution yields 0/0 or ∞/∞, differentiate top and bottom separately and re-evaluate; repeat if still indeterminate. It elegantly recovers the fundamental limits, e.g. lim_{x→0} sin x / x = lim cos x / 1 = 1.


Worked Examples

Example 1 (Motion — distance). For s(t) = t³ − 6t² + 9t + 1, find total distance on [0, 2]. v(t) = 3(t−1)(t−3), so it turns at t = 1. s(0) = 1, s(1) = 5, s(2) = 3. Distance = |5 − 1| + |3 − 5| = 4 + 2 = 6.

Example 2 (Speeding up?). v(t) = t² − 4, a(t) = 2t. At t = 3: v = 5 > 0 and a = 6 > 0 — same sign — so the particle is speeding up.

Example 3 (Related rates — balloon). Air enters a sphere at 100 cm³/s. How fast is r growing when r = 5? dV/dt = 4πr²(dr/dt)100 = 4π(25)(dr/dt) = 100π(dr/dt)dr/dt = 1/π cm/s.

Example 4 (Related rates — ladder). A 10-ft ladder's base slides out at 2 ft/s. When the base is 6 ft out, the top is 8 ft up. 2x·x' + 2y·y' = 02(6)(2) + 2(8)(y') = 0y' = −1.5 ft/s (sliding down).

Example 5 (Linearization). Approximate √4.1 with f(x) = √x at a = 4: f'(4) = 1/4, so L(4.1) = 2 + (1/4)(0.1) = 2.025.

Example 6 (L'Hôpital). lim_{x→0} (1 − cos x)/x² = (0/0) → lim sin x/(2x) = (0/0) → lim cos x/2 = 1/2.


✎ Self-Check — 5 questions0 / 5
Q1.A particle moves along a line with s(t) = t^3 - 6t^2 + 9t. On what interval is the particle moving to the right (v > 0)?
Explanation: v(t) = 3t^2 - 12t + 9 = 3(t - 1)(t - 3). This is positive when t < 1 or t > 3.
Q2.The position of an object is s(t) = -16t^2 + 64t (feet). What is its velocity at t = 1 second?
Explanation: v(t) = -32t + 64. At t = 1, v(1) = -32 + 64 = 32 ft/s.
Q3.An object is thrown upward with s(t) = -16t^2 + 64t. At what time does it reach its maximum height?
Explanation: Maximum height occurs when v(t) = -32t + 64 = 0, giving t = 2 seconds.
Q4.The speed of a particle is defined as:
Explanation: Speed is the magnitude of velocity, |v(t)|; it is always nonnegative and ignores direction.
Q5.A spherical balloon's volume is V = (4/3) pi r^3. The rate dV/dr equals:
Explanation: d/dr [(4/3) pi r^3] = (4/3) pi * 3 r^2 = 4 pi r^2 (which is the surface area).
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Module 4

Graphs, Pitfalls & AP Exam Tips

Graphical Interpretation, Common Mistakes & TipsTopic 1

Graphical Interpretation

  • The velocity graph's sign shows direction of motion; its zeros mark turning points; its own slope is acceleration.
  • Linearization is literally the tangent line; the approximation error grows with distance from a and with the curve's concavity.
  • A quantity increasing at a decreasing rate has f' > 0, f'' < 0 — rising but leveling off.

Common Mistakes

  • Omitting units or misreading the sign of a rate in context.
  • Confusing displacement with total distance (forgetting to split at v = 0).
  • Substituting numbers before differentiating in related rates — this freezes variables that are actually changing.
  • Forgetting the Chain Rule (dr/dt, dh/dt, …) when differentiating a related-rates relation.
  • Applying L'Hôpital to a non-indeterminate form (e.g., 1/0), or forgetting to re-check the form after one application.

AP Exam Tips

  • Related-rates and motion questions are free-response staples — practice clean set-ups and always state units.
  • Justify "speeding up/slowing down" by comparing the signs of v and a explicitly.
  • For approximations, state the linearization and note whether it's an over- or under-estimate using concavity.
  • Confirm the indeterminate form in writing before using L'Hôpital's Rule.

Unit Summary

  • A derivative in context has units and a sign — interpret both.
  • Motion: v = s', a = v'; speed = |v|; distance splits at v = 0; same-sign v, a ⇒ speeding up.
  • Related rates: relate → differentiate in t → substitute last.
  • Linearization L(x) = f(a) + f'(a)(x − a) approximates near a; concavity decides over/under.
  • L'Hôpital's Rule resolves 0/0 and ∞/∞ by differentiating top and bottom.

Next unit: use derivatives to analyze the shape of graphs — extrema, concavity, and optimization.

✎ Self-Check — 5 questions0 / 5
Q1.Water flows into a tank at a rate R(t) = t^2 gallons per minute. What does R'(t) represent?
Explanation: R(t) is already a rate (gallons/min). Its derivative R'(t) is the rate of change of that rate, with units gallons per minute per minute.
Q2.A particle has v(t) = t^2 - 4 and a(t) = 2t. At t = 3, is the particle speeding up or slowing down?
Explanation: At t = 3: v(3) = 5 > 0 and a(3) = 6 > 0. Since velocity and acceleration have the same sign, the particle is speeding up.
Q3.A particle has velocity v(t) = t^2 - 2t. At t = 3, the particle is:
Explanation: v(3) = 9 - 6 = 3 > 0 (moving right). a(t) = 2t - 2, so a(3) = 4 > 0. Same sign as v, so speeding up.
Q4.A particle has position s(t) = t^3 - 3t^2 - 9t. On what interval is it slowing down?
Explanation: v(t) = 3t^2 - 6t - 9 = 3(t-3)(t+1), zero at t = -1, 3. a(t) = 6t - 6, zero at t = 1. Slowing down where v and a have opposite signs: for t < -1 (v>0? check: at t=-2 v=3(−5)(−1)=15>0, a=−18<0 → opposite → slowing) and 1 < t < 3 (v<0, a>0 → opposite → slowing).
Q5.The temperature of an object is T(t) = 20 + 60e^(-0.1t) degrees. What is the rate of temperature change at t = 0?
Explanation: T'(t) = 60 * (-0.1) e^(-0.1t) = -6 e^(-0.1t). At t = 0, T'(0) = -6.

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