AP Calculus AB

Integration and Accumulation of Change

AP Calculus AB — Unit 6

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Module 1

Foundations & Definitions

Overview, Objectives & Key DefinitionsTopic 1

Unit Overview

This unit introduces the integral, the second pillar of calculus. Where the derivative measures instantaneous rate, the integral measures accumulated change — and, geometrically, area under a curve. You will build the integral from Riemann sums, connect it to antiderivatives through the Fundamental Theorem of Calculus (FTC), and develop core techniques (basic antiderivatives, properties of definite integrals, and u-substitution).

The FTC is the crown jewel: it ties differentiation and integration together as inverse processes. This unit is one of the largest on the exam.

Big picture: Integrating a rate gives the total (accumulated) change; the FTC lets you compute integrals using antiderivatives.


Learning Objectives

  • Approximate area/accumulation with left, right, and midpoint Riemann sums (and the Trapezoidal Rule).
  • Express a definite integral as a limit of Riemann sums.
  • State and apply both parts of the Fundamental Theorem of Calculus.
  • Use properties of definite integrals (additivity, constant multiple, reversing limits).
  • Find antiderivatives / indefinite integrals of basic functions.
  • Evaluate integrals using u-substitution and simple algebraic techniques.
  • Interpret accumulation functions g(x) = ∫ₐˣ f(t) dt.

Prerequisite Concepts

  • Differentiation (to recognize antiderivatives) and the Chain Rule (for u-substitution).
  • Summation and area of basic regions.
  • Domain awareness (ln|x| for 1/x, etc.).

Key Definitions

  • Antiderivative: F is an antiderivative of f if F'(x) = f(x). The indefinite integral is ∫ f(x) dx = F(x) + C.
  • Definite integral: ∫ₐᵇ f(x) dx = the limit of Riemann sums = signed area between f and the x-axis on [a, b].
  • Riemann sum: Σ f(xᵢ*) Δx over subintervals; using left, right, or midpoint sample points.
  • Accumulation function: g(x) = ∫ₐˣ f(t) dt — total accumulated amount from a to x.

✎ Self-Check — 5 questions0 / 5
Q1.If R(t) is the rate (gallons/min) at which water flows into a tank, what does the integral from 0 to 10 of R(t) dt represent?
Explanation: Integrating a rate of change over an interval gives the total accumulated change; here that is the total volume of water added from t = 0 to t = 10.
Q2.By the Fundamental Theorem of Calculus, d/dx of the integral from a to x of f(t) dt equals:
Explanation: FTC Part 1 states that if g(x) = integral from a to x of f(t) dt, then g'(x) = f(x).
Q3.The integral from a to a of f(x) dx equals:
Explanation: An integral over an interval of zero width is 0.
Q4.Evaluate the integral from 0 to 2 of x dx.
Explanation: An antiderivative is x^2/2. Evaluate: (2^2)/2 - 0 = 4/2 = 2.
Q5.What is the integral of x^3 dx?
Explanation: By the power rule for integration, integral of x^n = x^(n+1)/(n+1) + C. For n = 3: x^4/4 + C.
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Module 2

Theorems & Formulas

Important Theorems & FormulasTopic 1

Important Theorems

Fundamental Theorem of Calculus, Part 1 (FTC-1): If g(x) = ∫ₐˣ f(t) dt with f continuous, then g'(x) = f(x). With a variable upper limit u(x): d/dx ∫ₐ^{u(x)} f(t) dt = f(u(x))·u'(x) (Chain Rule).

Fundamental Theorem of Calculus, Part 2 (FTC-2): If F is any antiderivative of f, then ∫ₐᵇ f(x) dx = F(b) − F(a).

Riemann-sum over/under-estimates: for an increasing function, left sums underestimate and right sums overestimate (reverse for decreasing); for a concave-up function, the Trapezoidal Rule overestimates.


Important Formulas

Basic antiderivatives (add + C):

  • ∫ x^n dx = x^(n+1)/(n+1) for n ≠ −1; ∫ (1/x) dx = ln|x|
  • ∫ e^x dx = e^x; ∫ e^(kx) dx = (1/k)e^(kx)
  • ∫ cos x dx = sin x; ∫ sin x dx = −cos x
  • ∫ sec² x dx = tan x
  • ∫ 1/(1 + x²) dx = arctan x; ∫ 1/√(1 − x²) dx = arcsin x

Properties of definite integrals:

  • ∫ₐᵃ f = 0; ∫ₐᵇ f = −∫ᵦᵃ f
  • ∫ₐᵇ f + ∫ᵦᶜ f = ∫ₐᶜ f (additivity)
  • ∫ₐᵇ [k·f] = k∫ₐᵇ f; ∫ₐᵇ (f ± g) = ∫ₐᵇ f ± ∫ₐᵇ g (linearity)
  • Even function: ∫₋ₐᵃ f = 2∫₀ᵃ f; odd function: ∫₋ₐᵃ f = 0

✎ Self-Check — 5 questions0 / 5
Q1.A population changes at rate P'(t). The integral from 2 to 5 of P'(t) dt equals:
Explanation: By the Fundamental Theorem of Calculus, the integral of a rate P'(t) from 2 to 5 gives the net change P(5) - P(2).
Q2.A car's velocity is v(t) ft/s. The integral from 0 to 4 of v(t) dt (with v >= 0) represents:
Explanation: Integrating velocity over time gives displacement; when v >= 0, this equals the distance traveled.
Q3.Estimate the integral from 0 to 4 of f(x) dx using a right Riemann sum with 2 subintervals, given f(2) = 3 and f(4) = 5.
Explanation: Subinterval width = 2. Right sum uses right endpoints: 2*f(2) + 2*f(4) = 2(3) + 2(5) = 6 + 10 = 16.
Q4.Estimate the integral from 0 to 4 of f(x) dx using a left Riemann sum with 2 subintervals, given f(0) = 1 and f(2) = 3.
Explanation: Width = 2. Left sum uses left endpoints: 2*f(0) + 2*f(2) = 2(1) + 2(3) = 2 + 6 = 8.
Q5.For a decreasing function f, a right Riemann sum gives what kind of estimate?
Explanation: For a decreasing function, right endpoints give the smallest values on each subinterval, so the right Riemann sum underestimates the integral.
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Module 3

Concepts & Worked Examples

Concept Explanations & Solved ExamplesTopic 1

Concept Explanations

Accumulation (6.1, 6.5). Integrating a rate of change gives net change: ∫ₐᵇ f'(t) dt = f(b) − f(a). In context, "amount at time b" = "starting amount" + "accumulated change": f(b) = f(a) + ∫ₐᵇ f'(t) dt.

Riemann sums (6.2–6.3). Split [a, b] into n pieces of width Δx = (b − a)/n, sample the height at left/right/midpoints, and sum height × width. As n → ∞, the sum → the definite integral. Know which sampling over- or under-estimates based on monotonicity.

The FTC (6.4, 6.7). Part 2 turns area into arithmetic: find an antiderivative, evaluate at the bounds, subtract. Part 1 says differentiating an accumulation function recovers the integrand — the reason differentiation and integration are inverse operations.

u-Substitution (6.9). The reverse of the Chain Rule. Choose u to be an "inside" function whose derivative also appears (up to a constant). Substitute du, integrate in u, then convert back — or, for definite integrals, change the limits to u-values.

Algebraic set-up (6.10–6.11). Before integrating, simplify: split a fraction term-by-term, do long division on improper rational functions, or rewrite x²/(x²+1) = 1 − 1/(x²+1) so standard forms appear (leading to arctan, etc.).


Worked Examples

Example 1 (FTC-2). ∫₁³ x² dx = [x³/3]₁³ = 27/3 − 1/3 = 26/3.

Example 2 (Right Riemann sum). Estimate ∫₀⁴ f dx with 2 right rectangles, f(2) = 3, f(4) = 5: 2(3) + 2(5) = 16.

Example 3 (u-substitution). ∫ 2x(x² + 1)³ dx: let u = x² + 1, du = 2x dx → ∫ u³ du = u⁴/4 + C = (x² + 1)⁴/4 + C.

Example 4 (FTC-1 with Chain Rule). d/dx ∫₀^{x²} cos t dt = cos(x²)·2x = 2x cos(x²).

Example 5 (Properties). If ∫₀² f = 3 and ∫₂⁵ f = 7, then ∫₀⁵ f = 10; and ∫₀⁵ 5f = 50.

Example 6 (Accumulation in context). A bacteria culture grows at rate 3t (thousands/hour) from 5 thousand: amount after 2 h = 5 + ∫₀² 3t dt = 5 + [1.5t²]₀² = 5 + 6 = 11 thousand.

Example 7 (Absolute value). ∫₀² |x − 1| dx = ∫₀¹(1 − x)dx + ∫₁²(x − 1)dx = 1/2 + 1/2 = 1.


✎ Self-Check — 5 questions0 / 5
Q1.The definite integral from a to b of f(x) dx is defined as the limit of:
Explanation: The definite integral is defined as the limit of Riemann sums as the subinterval width approaches 0 (number of subintervals approaches infinity).
Q2.If g(x) = integral from 0 to x of (t^2 + 1) dt, what is g'(x)?
Explanation: By FTC Part 1, g'(x) equals the integrand evaluated at x: x^2 + 1.
Q3.FTC Part 2 states that the integral from a to b of f(x) dx equals:
Explanation: FTC Part 2: if F is any antiderivative of f, the definite integral from a to b of f equals F(b) - F(a).
Q4.Water flows out of a tank at rate r(t) liters/min. If the tank starts with 100 liters, the amount at time T is:
Explanation: Starting amount minus total outflow: 100 - (accumulated outflow) = 100 - integral from 0 to T of r(t) dt.
Q5.If f(0) = 20 and f'(t) is a known rate, then f(6) equals:
Explanation: The accumulation form: f(6) = f(0) + net change = 20 + integral from 0 to 6 of f'(t) dt.
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Module 4

Graphs, Pitfalls & AP Exam Tips

Graphical Interpretation, Common Mistakes & TipsTopic 1

Graphical Interpretation

  • A definite integral is signed area: area above the axis is positive, below is negative.
  • The accumulation function g(x) = ∫ₐˣ f: g increases where f > 0, decreases where f < 0, has a local max where f changes + → −, and is concave up where f is increasing.
  • Riemann rectangles visibly over/under-shoot depending on where the height is sampled.

Common Mistakes

  • Forgetting + C on indefinite integrals.
  • Sign error with ∫ sin x dx = −cos x (and the trig antiderivatives generally).
  • Not changing limits (or not converting back) in u-substitution.
  • Treating ∫ (1/x) dx as a power-rule case — it is ln|x|.
  • Mismatching Riemann over/under estimates — depends on increasing/decreasing (and concavity for trapezoids).
  • Dropping the u'(x) factor when differentiating an accumulation function with a non-x upper limit.

AP Exam Tips

  • FTC-2 is your workhorse for exact definite integrals; FTC-1 for derivatives of accumulation functions (watch the Chain Rule).
  • On accumulation free-response, write "amount = initial + ∫ rate" explicitly.
  • For estimates, state whether a sum is an over- or under-estimate and justify with monotonicity/concavity.
  • Recognize u-substitution when a factor is (a constant multiple of) the derivative of another part.
  • Use symmetry (odd/even) to shortcut integrals over symmetric intervals.

Unit Summary

  • The definite integral = limit of Riemann sums = signed area; integrating a rate gives accumulated change.
  • FTC-1: d/dx ∫ₐˣ f = f(x); FTC-2: ∫ₐᵇ f = F(b) − F(a).
  • Master basic antiderivatives, properties (additivity, linearity, symmetry), and u-substitution.
  • Accumulation functions inherit behavior from f via g' = f, g'' = f'.

Next unit: solving differential equations — recovering a function from its rate of change.

✎ Self-Check — 5 questions0 / 5
Q1.For an increasing function f, a left Riemann sum gives what kind of estimate of the definite integral?
Explanation: For an increasing function, left endpoints give the smallest values on each subinterval, so the left Riemann sum underestimates the integral.
Q2.Use a midpoint Riemann sum with 2 subintervals to estimate the integral from 0 to 4 of x^2 dx, using midpoints x = 1 and x = 3.
Explanation: Width = 2, midpoints 1 and 3: 2*f(1) + 2*f(3) = 2(1) + 2(9) = 2 + 18 = 20.
Q3.The expression lim (n->infinity) of the sum from i=1 to n of f(x_i) * (delta x) represents:
Explanation: This is the limit of a Riemann sum, which by definition is the definite integral of f over the interval.
Q4.The definite integral from 0 to 3 of (2x) dx can be interpreted geometrically as:
Explanation: The region under y = 2x from 0 to 3 is a triangle with base 3 and height 6, so the area (integral) is (1/2)(3)(6) = 9.
Q5.If g(x) = integral from 0 to x^2 of cos(t) dt, what is g'(x)?
Explanation: By FTC with the Chain Rule, g'(x) = cos(x^2) * d/dx(x^2) = cos(x^2) * 2x = 2x cos(x^2).

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