Limits and Continuity
AP Calculus AB — Unit 1
Foundations & Definitions
Overview, Objectives & Key DefinitionsTopic 1
Unit Overview
Limits are the foundation on which all of calculus is built. Before we can talk about instantaneous rates of change (derivatives) or accumulated change (integrals), we need a precise way to describe what a function approaches as its input gets arbitrarily close to some value. That idea — the limit — is what this unit develops.
By the end of this unit you should be able to reason about limits four ways: graphically, numerically, algebraically, and verbally, and connect them to the idea of continuity. On the AP exam, roughly 10–12% of the questions come from this unit, and the ideas reappear everywhere afterward.
Big picture: A limit answers the question, "Where is the function heading?" — regardless of whether it ever actually arrives.
Learning Objectives
After completing this unit you will be able to:
- Distinguish average rate of change (slope of a secant line) from instantaneous rate of change (slope of a tangent line).
- Express and evaluate limits using correct notation, including one-sided limits.
- Estimate limits from graphs and tables.
- Evaluate limits algebraically using limit laws, factoring, rationalization, and known trigonometric limits.
- Apply the Squeeze Theorem.
- Classify discontinuities (removable, jump, infinite) and remove removable ones.
- Determine continuity at a point and over an interval.
- Connect infinite limits to vertical asymptotes and limits at infinity to horizontal asymptotes.
- Apply the Intermediate Value Theorem (IVT).
Prerequisite Concepts
You should be comfortable with:
- Function notation and evaluation, domain and range.
- Factoring (difference of squares, difference of cubes, common factors) and rationalizing with conjugates.
- Piecewise functions and reading graphs.
- Basic trigonometry (unit-circle values, identities like tan = sin/cos).
- Rational functions and asymptote behavior from precalculus.
Key Definitions
- Limit: We write
lim_{x→c} f(x) = Lif the values of f(x) get arbitrarily close to L as x gets arbitrarily close to c (from both sides), without requiring x = c. - One-sided limits:
lim_{x→c⁻} f(x)(from the left) andlim_{x→c⁺} f(x)(from the right). - Existence of a two-sided limit:
lim_{x→c} f(x)exists iff both one-sided limits exist and are equal. - Average rate of change of f on [a, b]:
(f(b) − f(a)) / (b − a)— the slope of the secant line. - Instantaneous rate of change at x = a:
lim_{h→0} (f(a + h) − f(a)) / h— the slope of the tangent line. - Continuity at x = a: f is continuous at a if all three hold: (1) f(a) is defined, (2)
lim_{x→a} f(x)exists, (3)lim_{x→a} f(x) = f(a). - Removable discontinuity: a "hole" — the limit exists but does not equal f(a) (or f(a) is undefined).
- Jump discontinuity: the one-sided limits both exist but are unequal.
- Infinite discontinuity: the function grows without bound near the point (a vertical asymptote).
Theorems & Formulas
Important Theorems & FormulasTopic 1
Important Theorems
Limit Laws (valid when the individual limits exist). If lim f = L and lim g = M:
- Sum/Difference:
lim (f ± g) = L ± M - Constant multiple:
lim (k·f) = k·L - Product:
lim (f·g) = L·M - Quotient:
lim (f/g) = L/M, provided M ≠ 0 - Power/Root:
lim (f)^n = L^n
Squeeze (Sandwich) Theorem: If g(x) ≤ f(x) ≤ h(x) near c (except possibly at c) and lim_{x→c} g(x) = lim_{x→c} h(x) = L, then lim_{x→c} f(x) = L.
Intermediate Value Theorem (IVT): If f is continuous on [a, b] and N is any value between f(a) and f(b), then there exists at least one c in (a, b) with f(c) = N. (Guarantees existence, not the value or uniqueness.)
Continuity of common functions: Polynomials are continuous everywhere; rational, radical, trig, exponential, and log functions are continuous on their domains; sums, products, quotients (nonzero denominator), and compositions of continuous functions are continuous.
Important Formulas & Standard Limits
- Direct substitution (when f is continuous at c):
lim_{x→c} f(x) = f(c). - Fundamental trig limits:
lim_{x→0} (sin x)/x = 1lim_{x→0} (1 − cos x)/x = 0lim_{x→0} (tan x)/x = 1
- Limits at infinity of rational functions (compare degrees of numerator N and denominator D):
- deg N < deg D → limit is 0 (horizontal asymptote y = 0)
- deg N = deg D → limit is the ratio of leading coefficients
- deg N > deg D → no horizontal asymptote (limit is ±∞)
Concepts & Worked Examples
Concept Explanations & Solved ExamplesTopic 1
Concept Explanations
From average to instantaneous rate (1.1). The average rate of change over [a, b] is a secant slope you can compute directly. To get the instantaneous rate at a single point, shrink the interval: let the second point slide toward the first (h → 0). That limiting secant slope is the tangent slope — the derivative you'll define formally in Unit 2.
Why a limit ignores f(c) (1.2). The whole power of a limit is that it describes approach, not arrival. A function can have a limit of 3 at x = 4 while f(4) = 5, or while f(4) is undefined. This is exactly what lets us handle the 0/0 forms that derivatives produce.
Algebraic techniques (1.5–1.6). Try direct substitution first. If you get a real number, you're done. If you get 0/0 (indeterminate), do algebra: factor and cancel, rationalize with a conjugate, or use a known trig limit. If you get (nonzero)/0, the limit is infinite (check signs for ±∞).
Discontinuities and continuity (1.10–1.13). Test continuity with the three-part definition. A removable discontinuity can be "patched" by redefining f(c) to equal the limit. Jump and infinite discontinuities cannot be removed.
Asymptotes as limits (1.14–1.15). A vertical asymptote at x = c means a one-sided (or two-sided) limit is ±∞. A horizontal asymptote y = L means lim_{x→±∞} f(x) = L.
Worked Examples
Example 1 (Algebraic — factoring). Evaluate lim_{x→3} (x² − 9)/(x − 3).
Direct substitution gives 0/0. Factor: (x − 3)(x + 3)/(x − 3) = x + 3. So the limit is 3 + 3 = 6.
Example 2 (Rationalizing). Evaluate lim_{x→0} (√(x + 1) − 1)/x.
Multiply by the conjugate: ((x + 1) − 1) / (x(√(x+1) + 1)) = 1/(√(x+1) + 1). As x → 0 this is 1/(1 + 1) = 1/2.
Example 3 (Squeeze Theorem). Evaluate lim_{x→0} x² sin(1/x).
Since −1 ≤ sin(1/x) ≤ 1, we have −x² ≤ x² sin(1/x) ≤ x². Both bounds → 0, so the limit is 0.
Example 4 (Continuity — solve for a constant). Find k so that f is continuous at x = 2, where f(x) = kx² for x ≤ 2 and f(x) = x + k for x > 2.
Match the pieces: k(2)² = 2 + k → 4k = 2 + k → 3k = 2 → k = 2/3.
Example 5 (Limit at infinity). Evaluate lim_{x→∞} (3x² + 5)/(2x² − x).
Equal degrees → ratio of leading coefficients = 3/2.
Example 6 (IVT). Show f(x) = x³ − x − 1 has a root in [1, 2]. f is continuous; f(1) = −1 < 0 and f(2) = 5 > 0. Since 0 lies between −1 and 5, IVT guarantees a c in (1, 2) with f(c) = 0.
Graphs, Pitfalls & AP Exam Tips
Graphical Interpretation, Common Mistakes & TipsTopic 1
Graphical Interpretation
- A two-sided limit exists when the left and right branches of the graph head to the same height — even if there's a hole or the point is plotted elsewhere.
- A hole at (c, L) with the curve approaching L from both sides ⇒
lim = L(removable). - A jump (left branch heads to one height, right branch to another) ⇒ two-sided limit does not exist.
- A vertical asymptote ⇒ the branch shoots to ±∞ (infinite limit).
- A horizontal asymptote ⇒ the far-left/far-right tails flatten toward y = L.
Common Mistakes
- Assuming
lim_{x→c} f(x) = f(c)always. It only holds when f is continuous at c. - Stopping at 0/0 and writing "does not exist." 0/0 is indeterminate — do more algebra.
- Confusing "limit does not exist" with "= ∞". An infinite limit is a specific behavior; a jump is a different reason a limit fails.
- Forgetting to check both one-sided limits for piecewise functions and at asymptotes.
- Sign errors on infinite limits. Near a vertical asymptote, test the sign from each side to decide +∞ vs −∞.
- Misusing IVT. It requires continuity and only guarantees existence — never a specific value or uniqueness.
- Canceling a factor and forgetting the hole. After canceling (x − c), the original function still has a removable discontinuity at x = c.
AP Exam Tips
- Always try direct substitution first — it settles most non-calculator limits instantly.
- Memorize the three fundamental trig limits; they appear on both multiple-choice and free-response.
- For rational-function end behavior, compare degrees rather than doing long division under time pressure.
- On free-response, when citing IVT or discussing continuity, state that the function is continuous — that justification earns points.
- Read whether a question asks for the limit or the function value — they can differ.
- Calculator-active tables: use x-values very close on both sides to estimate a limit.
Unit Summary
- A limit describes where a function heads as x → c, independent of f(c).
- A two-sided limit exists iff both one-sided limits exist and are equal.
- Evaluate limits by substitution → algebra (factor/rationalize/trig) → interpret ∞.
- Continuity requires the value, the limit, and their equality; classify breaks as removable, jump, or infinite.
- Infinite limits ⇔ vertical asymptotes; limits at infinity ⇔ horizontal asymptotes.
- The Squeeze Theorem handles oscillating bounded functions; the IVT guarantees solutions for continuous functions.
Next unit: Unit 2 turns the instantaneous-rate idea into the formal derivative.