IMO Practice Test — Surface Chemistry

13 Questions • 15 min • Olympiad level

15:00
Question 1 of 13
For a given adsorbate at constant temperature, doubling the pressure increases $\frac{x}{m}$ by a factor of $\sqrt{2}$. The value of $n$ in the Freundlich isotherm is:
$2$
$1$
$\frac{1}{2}$
$4$
Explanation: If $\frac{x}{m}\propto p^{1/n}$ and a factor-2 pressure gives factor $2^{1/n}=2^{1/2}$, then $\frac{1}{n}=\frac{1}{2}$, so $n=2$.