Amines
Amines for JEE Main & Advanced
Structure, Preparation, and Basicity
Classification, Nomenclature, and PreparationTopic 1
Amines: Organic derivatives of $NH_3$ where one or more H is replaced by alkyl/aryl groups.
Classification (based on number of R groups on N):
| Type | Structure | Example |
|---|---|---|
| Primary (1°) | $R-NH_2$ (1 H replaced) | Methylamine ($CH_3NH_2$), aniline ($C_6H_5NH_2$) |
| Secondary (2°) | $R_2NH$ (2 H replaced) | Dimethylamine ($(CH_3)_2NH$), N-methylaniline |
| Tertiary (3°) | $R_3N$ (3 H replaced) | Trimethylamine ($(CH_3)_3N$), N,N-dimethylaniline |
| Quaternary ammonium | $R_4N^+X^-$ | $(CH_3)_4N^+Cl^-$ |
Also:
- Aliphatic ($R$ = alkyl): methylamine, ethylamine
- Aromatic ($R$ = aryl): aniline ($C_6H_5NH_2$)
- Mixed: N-methylaniline ($C_6H_5NHCH_3$)
Structure: N is $sp^3$ hybridized; pyramidal (like $NH_3$); lone pair on N.
- Bond angle ~$107°$ (slightly less than tetrahedral due to lp-bp repulsion)
Nomenclature:
| Compound | Common | IUPAC |
|---|---|---|
| $CH_3NH_2$ | Methylamine | Methanamine |
| $(CH_3)_2NH$ | Dimethylamine | N-methylmethanamine |
| $(CH_3)_3N$ | Trimethylamine | N,N-dimethylmethanamine |
| $C_6H_5NH_2$ | Aniline | Benzenamine (or aniline accepted) |
| $C_6H_5NHCH_3$ | N-methylaniline | N-methylbenzenamine |
Suffix: replace last 'e' of alkane with -amine. Substituents on N: prefix N-.
Preparation:
1. Reduction of Nitro Compounds: $RNO_2 + 6[H] \xrightarrow{Sn/HCl \text{ or } Fe/HCl \text{ or } H_2/Pt} RNH_2 + 2H_2O$
- For aniline: $C_6H_5NO_2 + 6[H] \to C_6H_5NH_2 + 2H_2O$
- Common reagents: $Sn + HCl$, $Fe + HCl$, $H_2/Ni$, $Zn/HCl$
2. Reduction of Nitriles ($RCN$): $RCN + 4[H] \xrightarrow{Na/C_2H_5OH \text{ or } LiAlH_4 \text{ or } H_2/Ni} RCH_2NH_2$
- Adds one C; 1° amine
- $CH_3CN \to CH_3CH_2NH_2$ (ethylamine, from methyl cyanide)
3. Reduction of Amides: $RCONH_2 + 4[H] \xrightarrow{LiAlH_4} RCH_2NH_2 + H_2O$
- Note: same number of C; 1° amine
4. Ammonolysis of Alkyl Halides (Hofmann's Method): $RX + NH_3 \to RNH_2 + HX$ (further alkylation possible)
- Gives mix of $1°, 2°, 3°$ amines and quaternary salt
- Order of reactivity: $RI > RBr > RCl$
- Industrial way for simple amines
Problems: over-alkylation. Solution: excess NH₃ for $1°$ amine; excess RX for higher amines.
5. Hofmann Bromamide Degradation: $RCONH_2 + Br_2 + 4NaOH \to RNH_2 + Na_2CO_3 + 2NaBr + 2H_2O$
- Amide → $1°$ amine with one fewer C
- Specific for $1°$ amine; no other isomers
- e.g., $CH_3CH_2CONH_2 \to CH_3CH_2NH_2$
6. Gabriel Phthalimide Synthesis: For pure $1°$ amines only.
- Potassium phthalimide + RX → N-alkyl phthalimide
- Hydrolyze (or hydrazine — Ing-Manske) → $RNH_2$ + phthalic acid
$\text{Phthalimide}-K + RX \to \text{Phthalimide}-R \xrightarrow{NaOH \text{ or } NH_2NH_2} RNH_2 + \text{phthalate}$
Limitations: Doesn't work with aryl halides (aryl C-X bond is unreactive in $S_N2$); doesn't give aryl amines.
Physical Properties:
- Lower amines: gases or liquids; pungent (fishy) smell
- BP: $RNH_2$ > $R_2NH$ > $R_3N$ (more H-bonding with more N-H bonds)
- BP order: $RNH_2 \approx ROH > R_3N \approx RH$ (alkanes)
- Solubility: lower amines very soluble in water (H-bond with water); decreases with chain length
- Aniline: oily liquid; turns brown on air exposure (auto-oxidation)
Predict products and identify if pure $1°$ amine: (a) $CH_3Br + NH_3$ (excess NH₃) (b) Gabriel phthalimide synthesis with $CH_3CH_2Br$.
Show solution
(a) With excess NH₃: $CH_3Br + NH_3 \to CH_3NH_2 + HBr$ (mostly $1°$, but some $2°, 3°$ also possible). (b) Gabriel: $CH_3CH_2Br$ + K-phthalimide → N-ethylphthalimide → hydrolyze → pure ethylamine ($CH_3CH_2NH_2$).
Final Answer: Gabriel gives pure $1°$ amine; ammonolysis gives mix.
Why doesn't Gabriel synthesis work for aniline?
Show solution
Gabriel synthesis requires reaction of phthalimide-K with alkyl halide via $S_N2$. Aryl halides ($C_6H_5X$) don't undergo $S_N2$ due to:
- Partial double-bond character in C-Cl (resonance)
- $sp^2$ C resistant to nucleophilic attack
- Steric hindrance from ring planar arrangement
Hence Gabriel can't make aryl amines.
Final Answer: Aryl halides don't undergo $S_N2$ — Gabriel only makes aliphatic primary amines.
$(CH_3)_3N$ is:
Reduction of nitrobenzene gives:
Gabriel synthesis cannot make:
Hofmann bromamide degradation gives:
Reduction of $CH_3CN$ gives:
Basicity of Amines (Gas vs Aqueous Phase)Topic 2
Basicity: Ability to donate lone pair to H⁺. Lone pair on N is key.
Comparison of Basicity:
- Amines are weaker bases than NaOH, KOH
- Amines are stronger bases than NH₃ (in general)
- $pK_b$ (or $pK_a$ of conjugate acid) measures basicity
Factors Affecting Basicity:
1. Inductive Effect (+I from alkyl): Alkyl groups donate electrons through sigma bonds → increases electron density on N → makes N more basic. Predicted order: $3° > 2° > 1° > NH_3$.
2. Resonance Effect: In aromatic amines, lone pair on N can delocalize into ring; reduces availability → less basic.
- Aniline < methylamine in basicity.
3. Steric Effect: Bulky groups around N prevent approach of H⁺ → decreases basicity. $(CH_3)_3N$ less basic than $(CH_3)_2NH$ in some scenarios.
4. Solvation Effect (Aqueous): $1°$ amine cation ($RNH_3^+$) has more H's available for H-bonding with water → better solvated → more stable → more basic effective. $3°$ amine cation ($R_3NH^+$) has only one N-H; less solvated → less stable → less basic in water.
Order of Basicity:
In Gas Phase (no solvation; only +I effect): $3° > 2° > 1° > NH_3$ $(CH_3)_3N > (CH_3)_2NH > CH_3NH_2 > NH_3$
In Aqueous Solution (combines +I and solvation): Generally: $2° > 1° > 3° > NH_3$ $(CH_3)_2NH > CH_3NH_2 > (CH_3)_3N > NH_3$
(Sometimes $1° > 2° > 3°$ if bulky groups cause more steric and less solvation.)
$pK_b$ values (aqueous, 25°C):
| Amine | $pK_b$ |
|---|---|
| $NH_3$ | $4.75$ |
| $CH_3NH_2$ | $3.36$ |
| $(CH_3)_2NH$ | $3.27$ (most basic) |
| $(CH_3)_3N$ | $4.20$ |
| Aniline | $9.42$ (very weak) |
| Pyridine | $8.85$ |
| Picoline | $\sim 8.0$ |
Basicity of Aromatic Amines:
Aniline < methylamine because:
- Lone pair on N delocalized into benzene ring via resonance (mesomeric effect)
- Lone pair less available for protonation
- Conjugate acid (anilinium ion) loses this resonance stabilization → less stable → less basic
Substituent Effects on Aniline:
| Substituent (at p-position) | Effect on Aniline Basicity |
|---|---|
| $-NO_2$ (p) | Strongly decreases (EW) |
| $-CN$ (p) | Decreases |
| $-Cl$, $-Br$ (p) | Decreases slightly (EW dominates over +R) |
| $-CH_3$ (p) | Increases (ED) |
| $-OCH_3$ (p) | Increases (ED, +R) |
| $-NH_2$ (p) | Increases (ED, +R) |
| $-OH$ (p) | Increases |
Effects in different positions:
- p-toluidine ($p$-$CH_3$): more basic than aniline (+I)
- p-nitroaniline: much less basic than aniline (-R, -I)
- o-nitroaniline: weakest of three nitroanilines (ortho effect, H-bonding internal)
Arrange in increasing basicity (aqueous): $NH_3$, $CH_3NH_2$, $(CH_3)_2NH$, $(CH_3)_3N$.
Show solution
In aqueous solution, considering both +I and solvation:
- $NH_3$: only H, full solvation of $NH_4^+$, but no +I (least basic by +I)
- $CH_3NH_2$: $1°$ amine, +I from CH₃, good solvation of $CH_3NH_3^+$
- $(CH_3)_2NH$: more +I, still 2 H's for solvation
- $(CH_3)_3N$: most +I but only 1 N-H for solvation; poor stabilization of cation
In aqueous: $NH_3 < (CH_3)_3N < CH_3NH_2 < (CH_3)_2NH$.
Final Answer: $NH_3 < (CH_3)_3N < CH_3NH_2 < (CH_3)_2NH$.
Arrange in increasing basicity: aniline, p-nitroaniline, p-toluidine, p-methoxyaniline.
Show solution
EW groups decrease basicity; ED groups increase.
- p-nitroaniline: $-NO_2$ strongly EW → very weak base
- aniline: standard
- p-toluidine: $-CH_3$ mild ED → slightly more basic
- p-methoxyaniline: $-OCH_3$ strong ED (+R) → most basic
Order: p-nitroaniline < aniline < p-toluidine < p-methoxyaniline.
Final Answer: p-nitroaniline < aniline < p-toluidine < p-methoxyaniline.
Most basic in gas phase:
Most basic in aqueous solution:
Aniline is less basic than methylamine because:
Most basic among:
Decrease in basicity from gas to aqueous of $(CH_3)_3N$ is due to:
Reactions of Amines
Reactions of Aliphatic Amines and TestsTopic 1
Reactions of Amines:
1. With Mineral Acids (Salt formation): $RNH_2 + HCl \to RNH_3^+Cl^-$ (alkyl ammonium chloride)
- Salts soluble in water; amines extracted by acidic workup
2. Alkylation (Hofmann's Method): $RNH_2 + R'X \to RR'NH + HX$ (→ further alkylation → $R_3N$ → $R_4N^+X^-$ quaternary salt)
- Gives mixture; isolated by fractional distillation/separation
3. Acylation (with acid chlorides or anhydrides): $RNH_2 + R'COCl \to R'CONHR + HCl$ (amide; "protected" amine) $RNH_2 + (R'CO)_2O \to R'CONHR + R'COOH$
- $3°$ amines don't acylate (no N-H)
- Acetylation of aniline → acetanilide ($C_6H_5NHCOCH_3$) — used in some old drugs
4. Carbylamine Reaction (Isocyanide Test) — for $1°$ amines: $RNH_2 + CHCl_3 + 3KOH \xrightarrow{\Delta} RNC + 3KCl + 3H_2O$
- Gives isocyanide with very offensive smell
- Specific test for $1°$ amines (both aliphatic and aromatic)
- $2°$ and $3°$ amines don't give this
5. Hinsberg Test (with Benzenesulfonyl Chloride):
- Distinguishes $1°, 2°, 3°$ amines.
| Amine | With $C_6H_5SO_2Cl$ (Benzenesulfonyl chloride) | + KOH (test) |
|---|---|---|
| $1°$ ($RNH_2$) | $C_6H_5SO_2NHR$ (sulfonamide; one N-H still) | Soluble in KOH (acidic NH due to strong EW $SO_2$) |
| $2°$ ($R_2NH$) | $C_6H_5SO_2NR_2$ (no N-H) | Insoluble in KOH (precipitate) |
| $3°$ ($R_3N$) | Doesn't react (no N-H to displace) | Amine recovered |
6. Reaction with Nitrous Acid (Diazotization):
(a) $1°$ Aliphatic amines + HNO₂ (cold) → unstable diazonium → loses $N_2$ → alcohol/alkene mix: $RNH_2 + HNO_2 \xrightarrow{0-5°C} ROH + N_2 + H_2O$ (Diazonium too unstable at any T)
(b) $1°$ Aromatic amines + HNO₂ at 0-5°C → stable arenediazonium salt: $ArNH_2 + HNO_2 + HCl \xrightarrow{0-5°C} ArN_2^+Cl^- + 2H_2O$
- Stable below $5°C$ (called diazotization)
(c) $2°$ amines + HNO₂ → N-nitrosoamines (yellow oily; carcinogenic): $R_2NH + HNO_2 \to R_2N-NO + H_2O$
(d) $3°$ amines + HNO₂: only protonates (no reaction at N-H since none).
7. Oxidation:
- Aniline + chromic acid → mostly degradation products; benzoquinone with some oxidants
- Aliphatic amines can give various products; not commonly used
Distinguish among $CH_3CH_2NH_2$ (1°), $(CH_3)_2NH$ ($2°$), $(CH_3)_3N$ ($3°$).
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Test 1: Carbylamine reaction (with $CHCl_3$ + alc. KOH):
- Only $1°$ amine gives offensive isocyanide smell → $CH_3CH_2NH_2$ positive.
- $(CH_3)_2NH$ and $(CH_3)_3N$ negative.
Test 2: Hinsberg test ($C_6H_5SO_2Cl$, then KOH):
- $(CH_3)_2NH$ gives a sulfonamide ($C_6H_5SO_2N(CH_3)_2$) insoluble in KOH.
- $(CH_3)_3N$ doesn't react; can be recovered as amine.
Final Answer: Carbylamine + Hinsberg identifies all three.
Predict products: (a) $C_6H_5NH_2 + (CH_3CO)_2O$ (b) $C_6H_5NH_2 + Br_2/H_2O$
Show solution
(a) Acylation: $C_6H_5NH_2 + (CH_3CO)_2O \to C_6H_5NHCOCH_3$ (acetanilide) $+ CH_3COOH$.
(b) Aniline is highly activated for EAS by $-NH_2$ (+R, strong activator). $Br_2$/water gives tribrominated product: $C_6H_5NH_2 + 3Br_2 \to 2,4,6$-tribromoaniline $+ 3HBr$ (white ppt).
Final Answer: (a) Acetanilide; (b) 2,4,6-tribromoaniline.
Hinsberg reagent:
Carbylamine test confirms:
With Hinsberg + KOH:
Aniline + cold HNO₂/HCl:
$RNH_2 + (CH_3CO)_2O$ gives:
Diazonium Salts and Aromatic AminesTopic 2
Aromatic Diazonium Salts ($ArN_2^+ X^-$): Extremely useful synthetic intermediates.
Preparation (Diazotization): $ArNH_2 + HNO_2 + HCl \xrightarrow{0-5°C} ArN_2^+Cl^- + 2H_2O$ (or $HNO_2$ generated in situ from $NaNO_2 + HCl$)
Conditions: low T (0-5°C); diazonium salt decomposes above 10°C.
Reactions of Diazonium Salts (extremely versatile):
A. Replacement of $N_2^+$ by Other Groups:
1. Sandmeyer Reaction: $ArN_2^+Cl^- + CuCl \to ArCl + N_2 + CuCl$ $ArN_2^+Br^- + CuBr \to ArBr + N_2 + CuBr$ $ArN_2^+Cl^- + CuCN \to ArCN + N_2$
- Replaces $N_2^+$ with Cl, Br, or CN
2. Gattermann Reaction: Variant with Cu/HCl or Cu/HBr (cheaper than Sandmeyer's Cu(I) salts): $ArN_2^+Cl^- + Cu/HCl \to ArCl + N_2 + CuCl$
3. Replacement by -I: With KI: $ArN_2^+Cl^- + KI \to ArI + N_2 + KCl$ (no catalyst needed; smooth)
4. Replacement by -F (Schiemann): $ArN_2^+BF_4^- \xrightarrow{\Delta} ArF + N_2 + BF_3$
5. Replacement by -OH (Hydrolysis): $ArN_2^+ + H_2O \xrightarrow{warm} ArOH + N_2 + H^+$ (gives phenol; warm dilute acid solution)
6. Replacement by -H (Deamination): $ArN_2^+ + H_3PO_2 \to ArH + N_2 + H_3PO_3$ (or hypophosphorous acid; useful for removing $-NH_2$ from ring)
7. Replacement by -NO₂: With Cu/NaNO₂.
B. Azo Coupling Reactions (Retention of $N_2$):
Diazonium ions are weak electrophiles; couple with strongly activated aromatics (phenols, anilines):
$ArN_2^+ + Ar'H \to Ar-N=N-Ar' + H^+$
Conditions:
- With phenols: alkaline solution (pH 9-10): the phenoxide $Ar'O^-$ is highly activated; couples at para position.
- With aromatic amines: acidic to neutral (pH 5-7): amine itself activated.
Examples:
- Aniline + diazonium → orange dye (methyl orange in industry made from diazotized sulfanilic acid + N,N-dimethylaniline)
- Phenol + diazonium → orange-red dye (p-hydroxyazobenzene)
Reactivity: Used in azo dyes industry (clothes, paper, food coloring).
Importance of $ArN_2^+$: Convert $-NH_2$ to many functional groups (-OH, -X, -CN, -NO₂, -H, -Ar) — making it a versatile route in aromatic synthesis.
Aromatic Amines Reactions Summary:
Aniline ($C_6H_5NH_2$) Properties:
- Lone pair on N donates to ring → strong activator, o/p director (for EAS).
- Less basic than aliphatic amines (resonance lock-up of lp).
- Cannot undergo Friedel-Crafts directly (Lewis acid forms complex with lone pair on N, deactivating ring).
- Solution: protect $-NH_2$ as $-NHCOCH_3$ (acetanilide) first.
EAS on Aniline:
- Bromination ($Br_2$/water): 2,4,6-tribromoaniline (uncontrolled; aniline very activated).
- Mono-bromination requires acetanilide protection, then deprotection.
- Nitration:
- Direct $HNO_3 + H_2SO_4$: aniline gets protonated ($-NH_3^+$, m-director) → m-nitroaniline major (~50%) + o, p
- To get p-nitroaniline: protect as acetanilide → nitrate → mostly para → hydrolyze.
Coupling reactions:
- Aniline + nitrous acid → diazonium salt (then various reactions above)
- Diazonium coupling with phenol/amine → azo dye
Convert aniline to: (a) chlorobenzene (b) phenol (c) iodobenzene (d) fluorobenzene
Show solution
All via diazonium salt intermediate: $C_6H_5NH_2 \xrightarrow{HNO_2/HCl, 0-5°C} C_6H_5N_2^+Cl^-$ (a) Sandmeyer: + CuCl → $C_6H_5Cl + N_2$ (b) Hydrolyze: + $H_2O$/warm → $C_6H_5OH + N_2 + H^+$ (c) Direct: + KI → $C_6H_5I + N_2 + KCl$ (d) Schiemann: + $HBF_4$ → $C_6H_5N_2^+BF_4^-$ → $\Delta$ → $C_6H_5F + N_2 + BF_3$.
Final Answer: All via diazotization, then specific reagent.
Why does coupling of $C_6H_5N_2^+$ work with phenol but only at right pH?
Show solution
Coupling is EAS where $ArN_2^+$ is electrophile. Phenol's reactivity depends on pH:
- In alkaline (pH 9-10): Phenol becomes $C_6H_5O^-$ (phenoxide). Strongly activated for EAS by $-O^-$ (strong +R donor). Couples at para position to give $p$-hydroxy azobenzene (orange dye).
- In strongly acidic (low pH): Phenol is mostly $C_6H_5OH$; not as activated. $ArN_2^+$ also less reactive.
- In strongly alkaline: $ArN_2^+$ converts to $ArN=N-OH$ (covalent diazohydroxide, not electrophilic).
Optimal: slightly alkaline (pH 9-10).
Final Answer: Need pH where phenoxide forms (good Nu) but diazonium remains ionic (still electrophile).
Sandmeyer reaction:
Schiemann reaction gives:
Coupling of $ArN_2^+$ with phenol gives:
Aniline + Friedel-Crafts:
Convert $C_6H_5NH_2$ to $C_6H_5OH$:
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