Mock Test 1 — Amines

$C_6H_5NHCH_3$ is:

Strongest base in aqueous medium:

Gabriel phthalimide synthesis gives:

Carbylamine test reagent:

Diazotization is done at:

Aniline is less basic than methylamine because:

Hinsberg test for $2°$ amine:

Anilinium sulfate is:

p-Nitroaniline basicity vs aniline:

Coupling of $ArN_2^+$ with $C_6H_5OH$ gives:

Number of H's on N in primary amine:

Number of H's on N in $(CH_3)_3N$:

Number of $1°$ amines from Gabriel synthesis (with one alkyl halide):

Assertion (A): Aniline gives carbylamine reaction. Reason (R): Aniline is a primary amine; with CHCl₃/KOH it forms phenyl isocyanide.

Assertion (A): Diazonium salts are useful synthetic intermediates. Reason (R): They can be converted to a wide range of aromatic compounds (ArCl, ArBr, ArI, ArOH, ArCN, ArF, ArH, ArNO₂, ArAr) by various reactions.