Image formed by a plane mirror is:
A convex lens of $f = 20$ cm is used to view an object placed $10$ cm away. The image is:
Refractive index of medium where speed of light is $2 \times 10^8$ m/s:
The critical angle for diamond ($n = 2.42$) is approximately:
In YDSE, the maximum number of bright fringes formed on a screen of width $W$ (with slit separation $d$, wavelength $\lambda$):
Two coherent sources of equal intensity superpose. Ratio of maximum to minimum intensity:
The polarizing angle for a medium:
A converging lens of $f = 10$ cm; object at $20$ cm. Image distance:
Two slits in YDSE are illuminated by light of wavelengths $400$ nm and $600$ nm. Position of first coincidence of bright fringes from centre (in terms of $\lambda$):
Power of a lens of focal length $25$ cm:
A prism of $A = 60°$, minimum deviation $30°$. The refractive index $n$ to two decimal places, then multiplied by $100$ (rounded integer):
In YDSE: $d = 0.5$ mm, $D = 1$ m, $\lambda = 500$ nm. Fringe width in mm:
An object of $4$ cm is placed $30$ cm from a concave mirror of $f = 15$ cm. Image height (magnitude in cm, integer):
Assertion (A): A convex mirror is used as a rear-view mirror in vehicles. Reason (R): It produces a virtual, erect, diminished image with a wide field of view.
Assertion (A): Two independent sources cannot produce sustained interference. Reason (R): They emit light of different frequencies and have random phase difference.
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