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Vidaara.orgClass 10 · Mathematics
CodeVID-M10-01-IRR-01
Revisiting Irrational Numbers — Assignment
Chapter: Number Systems
Topic: Revisiting Irrational Numbers
Maximum Marks: 35
Time: 75 minutes
Name: ____________________ Roll No.: __________ Date: ____________

General Instructions

  • All questions are compulsory.
  • Section A carries 1 mark each, Section B 2 marks, Section C 3 marks and Section D 5 marks.
  • Show all working for Sections B, C and D. Only final answers are given at the end — for full solutions, raise your doubts with your teacher.
Section A — Multiple Choice Questions 5 × 1 = 5 marks
1.
$\sqrt2$ is:
  • A.rational
  • B.irrational
  • C.an integer
  • D.zero
2.
The product of a non-zero rational and an irrational is:
  • A.rational
  • B.irrational
  • C.zero
  • D.an integer
3.
$\sqrt9$ is:
  • A.irrational
  • B.rational
  • C.not real
  • D.negative
4.
$\pi$ is:
  • A.rational
  • B.irrational
  • C.terminating
  • D.an integer
5.
A non-terminating non-repeating decimal is:
  • A.rational
  • B.irrational
  • C.an integer
  • D.terminating
Section B — Short Answer (2 marks) 4 × 2 = 8 marks
6.
Is $3+\sqrt2$ rational or irrational?
7.
Is $\sqrt{16}$ rational?
8.
Classify $2\sqrt3$.
9.
Is $0.\overline{3}$ rational?
Section C — Short Answer (3 marks) 4 × 3 = 12 marks
10.
Prove that $\sqrt2$ is irrational (state the method).
11.
Show that $5-\sqrt3$ is irrational.
12.
Show that $3\sqrt2$ is irrational.
13.
Is $\sqrt2+\sqrt3$ rational or irrational?
Section D — Long Answer (5 marks) 2 × 5 = 10 marks
14.
Prove that $\sqrt5$ is irrational.
15.
Prove that $3+2\sqrt5$ is irrational, given that $\sqrt5$ is irrational.

Answer Key

Section A — Multiple Choice Questions
  1. (B) irrational
  2. (B) irrational
  3. (B) rational
  4. (B) irrational
  5. (B) irrational
Section B — Short Answer (2 marks)
  1. Irrational.
  2. Yes ($=4$).
  3. Irrational.
  4. Yes ($=\tfrac13$).
Section C — Short Answer (3 marks)
  1. By contradiction; $\sqrt2$ is irrational.
  2. Irrational.
  3. Irrational.
  4. Irrational.
Section D — Long Answer (5 marks)
  1. By contradiction, $\sqrt5$ is irrational.
  2. Irrational.
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