Vidaara.orgClass 10 · Mathematics
CodeVID-M10-03-ALG-01
Algebraic Methods — Assignment
Name: ____________________
Roll No.: __________
Date: ____________
General Instructions
- All questions are compulsory.
- Section A carries 1 mark each, Section B 2 marks, Section C 3 marks and Section D 5 marks.
- Show all working for Sections B, C and D. Only final answers are given at the end — for full solutions, raise your doubts with your teacher.
Section A — Multiple Choice Questions
5 × 1 = 5 marks
1.
In substitution we express:
- A.both as constants
- B.one variable in terms of the other
- C.the sum
- D.nothing
2.
The three methods include substitution, elimination and:
- A.graphing
- B.cross-multiplication
- C.trial
- D.division
3.
Solving $x+y=10,\ x-y=4$ gives $x=$
- A.$5$
- B.$7$
- C.$3$
- D.$6$
4.
If $2x=8$ then $x=$
- A.$2$
- B.$4$
- C.$6$
- D.$16$
5.
Cross-multiplication uses the coefficients of:
- A.one equation
- B.both equations
- C.neither
- D.only constants
Section B — Short Answer (2 marks)
4 × 2 = 8 marks
6.
Solve $x+y=6,\ x-y=2$.
7.
Solve $2x+y=7$ with $x=2$.
8.
Solve by elimination: $x+y=5,\ 2x-y=4$.
9.
Solve $x-y=3,\ x+y=9$.
Section C — Short Answer (3 marks)
4 × 3 = 12 marks
10.
Solve by substitution: $2x+3y=12,\ x-y=1$.
11.
Solve by elimination: $3x+2y=12,\ 5x-2y=4$.
12.
Solve $2x+y=5,\ 3x+2y=8$.
13.
Solve $x+y=9,\ x-y=1$.
Section D — Long Answer (5 marks)
2 × 5 = 10 marks
14.
Solve $2x+3y=11$ and $2x-4y=-24$; then find $m$ if $y=mx+3$.
15.
Solve by cross-multiplication: $8x+5y=9,\ 3x+2y=4$.
Answer Key
Section A — Multiple Choice Questions
- (B) one variable in terms of the other
- (B) cross-multiplication
- (B) $7$
- (B) $4$
- (B) both equations
Section B — Short Answer (2 marks)
- $x=4,\ y=2$.
- $y=3$.
- $x=3,\ y=2$.
- $x=6,\ y=3$.
Section C — Short Answer (3 marks)
- $x=3,\ y=2$.
- $x=2,\ y=3$.
- $x=2,\ y=1$.
- $x=5,\ y=4$.
Section D — Long Answer (5 marks)
- $x=-2,\ y=5,\ m=-1$.
- $x=-2,\ y=5$.
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