Vidaara.orgClass 10 · Mathematics
CodeVID-M10-16-CON-01
Continued Proportion — Assignment
Name: ____________________
Roll No.: __________
Date: ____________
General Instructions
- All questions are compulsory.
- Section A carries 1 mark each, Section B 2 marks, Section C 3 marks and Section D 5 marks.
- Show all working for Sections B, C and D. Only final answers are given at the end — for full solutions, raise your doubts with your teacher.
Section A — Multiple Choice Questions
5 × 1 = 5 marks
1.
If $a:b::b:c$, then:
- A.$b^2=ac$
- B.$b=ac$
- C.$a^2=bc$
- D.$c=ab$
2.
$b$ is the mean proportional of $a,c$ if:
- A.$b=a+c$
- B.$b^2=ac$
- C.$b=ac$
- D.$2b=ac$
3.
The mean proportional between $4$ and $9$ is:
- A.$6$
- B.$13$
- C.$36$
- D.$5$
4.
In continued proportion $a,b,c$, $c$ is the:
- A.mean proportional
- B.third proportional
- C.ratio
- D.first term
5.
If $4,x,9$ are in continued proportion, $x^2=$
- A.$13$
- B.$36$
- C.$5$
- D.$94$
Section B — Short Answer (2 marks)
4 × 2 = 8 marks
6.
Find the mean proportional between $4$ and $16$.
7.
Find the third proportional to $4$ and $8$.
8.
If $a:b=2:3$, find $\tfrac{a}{b}$.
9.
Are $2,4,8$ in continued proportion?
Section C — Short Answer (3 marks)
4 × 3 = 12 marks
10.
Find the mean proportional between $9$ and $25$.
11.
Find the third proportional to $9$ and $12$.
12.
Find $x$ if $4,x,9$ are in continued proportion.
13.
If $a:b=3:4$ and $b:c=2:5$, find $a:b:c$.
Section D — Long Answer (5 marks)
2 × 5 = 10 marks
14.
The mean proportional between two numbers is $12$ and their third proportional is $96$. Find the numbers.
15.
If $\dfrac{a}{b}=\dfrac{c}{d}$, prove that $\dfrac{a+b}{b}=\dfrac{c+d}{d}$ (componendo).
Answer Key
Section A — Multiple Choice Questions
- (A) $b^2=ac$
- (B) $b^2=ac$
- (A) $6$
- (B) third proportional
- (B) $36$
Section B — Short Answer (2 marks)
- $8$.
- $16$.
- $\tfrac23$.
- Yes ($4^2=2\times8$).
Section C — Short Answer (3 marks)
- $15$.
- $16$.
- $x=6$.
- $3:4:10$.
Section D — Long Answer (5 marks)
- $6$ and $24$.
- $\dfrac{a+b}{b}=\dfrac{c+d}{d}$.
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