Online Test — Coordinate Geometry
10 Questions • 15 min • Chapter MCQ
15:00
Question 1 of 10
medium
Find the distance between points (2, 3) and (5, 7).
4
5
6
7
Explanation: √[(5-2)\(^{2}\)+(7-3)\(^{2}\)]=\(\sqrt{9+16}\)=\(\sqrt{25}\)=5
Question 2 of 10
medium
The distance of point P(3, 4) from the origin is:
3
4
5
7
Explanation: \(\sqrt{3^{2}+4^{2}}\)=\(\sqrt{25}\)=5
Question 3 of 10
medium
The midpoint of (4, 6) and (8, 10) is:
(6,8)
(5,7)
(7,9)
(12,16)
Explanation: ((4+8)/2, (6+10)/2) = (12/2, 16/2) = (6,8)
Question 4 of 10
medium
Reflection of (−2, 5) in the x-axis is:
(2,5)
(−2,−5)
(2,−5)
(5,−2)
Explanation: x-coordinate stays same, y changes sign: (−2,−5)
Question 5 of 10
medium
The area of triangle with vertices (0,0), (3,0), (0,4) is:
6
8
12
24
Explanation: Area=½×base×height=½×3×4=6
Question 6 of 10
medium
Find the ratio in which the point (3,5) divides the join of (1,3) and (5,7) internally.
1:1
1:2
2:1
3:1
Explanation: Using x:3=(5m+1n)/(m+n)→3m+3n=5m+n→2n=2m→m:n=1:1
Question 7 of 10
medium
For points (a,0), (0,b), and (0,0) to be collinear, we must have:
a=0
b=0
a=b
ab=0
Explanation: The triangle with vertices $(a,0),(0,b),(0,0)$ has area $\frac{1}{2}|ab|$. The points are collinear when this area is zero, i.e. $ab=0$.
Question 8 of 10
medium
Reflection of (4, −7) in the y-axis is:
(4,7)
(−4,−7)
(−4,7)
(7,4)
Explanation: y-axis reflection: (−4,−7)
Question 9 of 10
medium
The points (1,1), (2,3), and (4,7) are:
Form a right triangle
Collinear
Form an isosceles triangle
Form an equilateral triangle
Explanation: Slope AB=2, slope BC=2, slope AC=2 → all equal → collinear
Question 10 of 10
medium
If P(2,3) is the midpoint of AB with A(4,5), then B is:
(0,1)
(1,0)
(6,7)
(8,10)
Explanation: Midpoint formula: (4+\(x_{2}\))/2=2→\(x_{2}\)=0; (5+\(y_{2}\))/2=3→\(y_{2}\)=1