Online Test — Polynomials
10 Questions • 15 min • Chapter MCQ
15:00
Question 1 of 10
medium
Which of the following is a zero of p(x) = \(x^{2} - 7x + 12\)?
2
3
5
6
Explanation: p(3)=9−21+12=0; also p(4)=0, but 3 is an option ✓
Question 2 of 10
medium
How many zeros can a quadratic polynomial have at most?
1
2
3
4
Explanation: Degree = 2 → maximum 2 zeros
Question 3 of 10
medium
For the polynomial p(x) = \(2x^{2} - 8x + 6\), the sum of zeros is:
4
−4
3
−3
Explanation: Sum = −b/a = −(−8)/2 = 8/2 = 4
Question 4 of 10
medium
If one zero of \(x^{2} - 5x + k\) is 2, then k = ?
4
5
6
7
Explanation: p(2)=4−10+k=0 → k=6
Question 5 of 10
medium
The product of zeros of p(x) = \(4x^{2} - 9\) is:
9/4
−9/4
9
−9
Explanation: c/a = −9/4 (since c=−9, a=4)
Question 6 of 10
medium
Which of these is a zero of the linear polynomial 4x − 20?
4
5
20
−5
Explanation: 4x−20=0 → x=5
Question 7 of 10
medium
Find the quadratic polynomial whose zeros are 2 and −3.
\(x^{2} + x - 6\)
\(x^{2} - x + 6\)
\(x^{2} - x - 6\)
\(x^{2} + x + 6\)
Explanation: Sum=−1, Product=−6 → \(x^{2}\)−(−1)x+(−6)=\(x^{2}+x-6\)
Question 8 of 10
medium
If α and β are zeros of \(x^{2} + 4x - 12\), then α + β = ?
4
−4
12
−12
Explanation: α+β = −b/a = −4/1 = −4
Question 9 of 10
medium
The value of p(2) for p(x) = \(x^{3} - 2x^{2} + x - 2\) is:
0
2
4
6
Explanation: 8−8+2−2=0, so x=2 is a zero
Question 10 of 10
medium
For quadratic \(ax^{2} + bx + c\), if α+β = 0, then:
b = 0
c = 0
a = 0
α = β = 0
Explanation: α+β = −b/a = 0 → −b=0 → b=0