Introduction to Three Dimensional Geometry • Topic 1 of 3

Coordinate Axes, Coordinate Planes and Octants

In Class 10 you fixed the position of a point in a plane with two numbers $(x, y)$. To locate a point in space you need a third measurement — how far the point sits above or below that plane — so every point now carries an ordered triple $(x, y, z)$. The word "ordered" matters: $(2, 3, 5)$ and $(5, 3, 2)$ are completely different points.

The three coordinate axes. Take three mutually perpendicular lines meeting at a single point $O$, the origin. These are the $x$-axis, the $y$-axis and the $z$-axis. Each axis is an ordinary number line — positive on one side of $O$, negative on the other. The three axes are drawn following the right-hand rule: if the fingers of the right hand curl from the positive $x$-axis toward the positive $y$-axis, the thumb points along the positive $z$-axis. This convention keeps everyone's diagrams consistent.

$$\text{A point in space} \;\longleftrightarrow\; \text{an ordered triple } (x,\ y,\ z)$$

The three coordinate planes. Taken two axes at a time, the axes determine three flat planes that slice space apart. Each plane is named after the two axes lying in it, and on that plane the third coordinate is always zero.

PlaneContains axesEquationPoints on it satisfy
$XY$-plane$x$- and $y$-axis$z = 0$third coordinate is $0$
$YZ$-plane$y$- and $z$-axis$x = 0$first coordinate is $0$
$ZX$-plane$z$- and $x$-axis$y = 0$second coordinate is $0$

Reading and locating the coordinates of a point. For a point $P(x, y, z)$, the number $x$ is the perpendicular distance of $P$ from the $YZ$-plane, $y$ the distance from the $ZX$-plane and $z$ the distance from the $XY$-plane — each taken with its proper sign. To plot $P$ you can follow a simple route: start at $O$, walk $x$ units along the $x$-axis, then $y$ units parallel to the $y$-axis, then $z$ units parallel to the $z$-axis. Geometrically $P$ is the far corner of a rectangular box (a cuboid) whose three edges from the origin have lengths $|x|$, $|y|$, $|z|$ along the three axes.

Special positions. A point lies on an axis when its other two coordinates are zero — for example $(5, 0, 0)$ is on the $x$-axis, $(0, -2, 0)$ on the $y$-axis, $(0, 0, 7)$ on the $z$-axis. A point lies on a coordinate plane when exactly one coordinate is zero — $(3, -4, 0)$ on the $XY$-plane, and so on. All three coordinates zero gives the origin itself.

The eight octants. Just as the two axes cut a plane into four quadrants, the three coordinate planes cut space into eight compartments called octants. An octant is fixed entirely by the sign pattern of its points. The first octant is the all-positive region; the standard numbering is given below.

Octant$x$$y$$z$Example point
I$+$$+$$+$$(2, 3, 4)$
II$-$$+$$+$$(-2, 3, 4)$
III$-$$-$$+$$(-2, -3, 4)$
IV$+$$-$$+$$(2, -3, 4)$
V$+$$+$$-$$(2, 3, -4)$
VI$-$$+$$-$$(-2, 3, -4)$
VII$-$$-$$-$$(-2, -3, -4)$
VIII$+$$-$$-$$(2, -3, -4)$

Two helpful checks fall out of this table. The top four octants (I–IV) all have $z > 0$ and the bottom four (V–VIII) have $z < 0$, so the sign of $z$ alone tells you whether a point is above or below the $XY$-plane. And octants I–IV, read in the $(x, y)$ signs, are exactly the four quadrants of the $XY$-plane lifted upward.

Deeper Insight — three dimensions as two dimensions plus a height: The whole framework of 3D geometry is built by bolting one more perpendicular axis onto the familiar 2D plane, and almost every formula you meet later is the 2D version with a single extra term tagged on. Notice the symmetry running through the octant table: the first four octants are the four quadrants of the $XY$-plane "lifted" into positive $z$, and octants V–VIII are their mirror images below it — the top four all carry $z > 0$ and the bottom four $z < 0$. This is why a zero coordinate is so informative: one zero pins the point to a coordinate plane, two zeros pin it to an axis, and three zeros give the origin. Hold this "plane plus height" picture firmly and the distance and section formulas in the next two topics will feel like old friends rather than new rules.

Three dimensional coordinate axes with a labelled point P(x, y, z) 3D Axes and the Point P(x, y, z) x y z O P(x, y, z) xyz The first octant carries all positive coordinates First Octant: all coordinates positive +x +y +z (+, +, +)
1
Worked Example
Name the octant in which each point lies: $A(3, -2, 5)$, $B(-4, -1, -6)$, $C(-2, 5, 1)$.
Solution
  1. $A(3, -2, 5)$ has signs $(+, -, +)$ — that is octant IV.
  2. $B(-4, -1, -6)$ has signs $(-, -, -)$ — that is octant VII.
  3. $C(-2, 5, 1)$ has signs $(-, +, +)$ — that is octant II.

Answer: $A$ in octant IV, $B$ in octant VII, $C$ in octant II.

2
Worked Example
On which coordinate plane or axis does each point lie: $P(0, 4, -3)$, $Q(7, 0, 0)$, $R(2, -5, 0)$?
Solution
  1. $P(0, 4, -3)$: the $x$-coordinate is $0$, so $P$ lies on the $YZ$-plane.
  2. $Q(7, 0, 0)$: both $y$ and $z$ are $0$, so $Q$ lies on the $x$-axis.
  3. $R(2, -5, 0)$: the $z$-coordinate is $0$, so $R$ lies on the $XY$-plane.

Answer: $P$ on the $YZ$-plane, $Q$ on the $x$-axis, $R$ on the $XY$-plane.

3
Worked Example
Find the coordinates of the feet of the perpendiculars drawn from $P(3, -4, 5)$ to each of the three coordinate planes.
Solution
  1. Foot on the $XY$-plane: set $z = 0$, keep $x, y$ — gives $(3, -4, 0)$.
  2. Foot on the $YZ$-plane: set $x = 0$ — gives $(0, -4, 5)$.
  3. Foot on the $ZX$-plane: set $y = 0$ — gives $(3, 0, 5)$.

Answer: $(3, -4, 0)$ on $XY$, $(0, -4, 5)$ on $YZ$, $(3, 0, 5)$ on $ZX$.

4
Worked Example
The point $(x, y, z)$ lies in octant VI. Write the sign of each coordinate, and give one such point.
Solution
  1. From the octant table, octant VI has the sign pattern $(-, +, -)$.
  2. So $x < 0$, $y > 0$ and $z < 0$.
  3. A convenient example is $(-1, 4, -2)$.

Answer: Signs $(-, +, -)$; one such point is $(-1, 4, -2)$.

5
Worked Example
A point $P$ has $x$-coordinate $6$, $z$-coordinate $-2$ and lies on the $ZX$-plane. Find $P$.
Solution
  1. The $ZX$-plane is defined by $y = 0$.
  2. So the $y$-coordinate of $P$ must be $0$.
  3. Combine with the given $x = 6$ and $z = -2$.

Answer: $P = (6, 0, -2)$.

6
Worked Example
Find the image (reflection) of the point $A(2, 3, 4)$ in (a) the $XY$-plane and (b) the $x$-axis.
Solution
  1. (a) Reflecting in the $XY$-plane reverses the sign of $z$ only: $(2, 3, -4)$.
  2. (b) Reflecting in the $x$-axis keeps $x$ but reverses both $y$ and $z$: $(2, -3, -4)$.

Answer: (a) $(2, 3, -4)$; (b) $(2, -3, -4)$.

7
Worked Example
Plot, in words, the steps to locate $P(2, -3, 4)$ starting from the origin, and state which octant it lies in.
Solution
  1. From $O$, move $2$ units along the positive $x$-axis.
  2. Then move $3$ units in the negative $y$-direction (parallel to the $y$-axis).
  3. Then move $4$ units in the positive $z$-direction (parallel to the $z$-axis).
  4. The sign pattern $(+, -, +)$ is octant IV.

Answer: $P(2, -3, 4)$ is reached by the moves $2,\ -3,\ 4$ along the three axis directions; it lies in octant IV.

8
Worked Example
A point lies on the $z$-axis at a distance $5$ on the negative side of the origin. Write its coordinates, and explain why two of its coordinates must be zero.
Solution
  1. On the $z$-axis a point has no spread in the $x$- or $y$-direction, so $x = 0$ and $y = 0$.
  2. "Distance $5$ on the negative side" means $z = -5$.

Answer: The point is $(0, 0, -5)$; its $x$- and $y$-coordinates are $0$ because the $z$-axis is the set of points with $x = y = 0$.

9
Worked Example
Name the octant of each point and state how many of the eight octants are represented: $(1, 1, 1)$, $(-1, 1, 1)$, $(1, -1, -1)$, $(-1, -1, -1)$.
Solution
  1. $(1, 1, 1)$ has signs $(+, +, +)$ — octant I.
  2. $(-1, 1, 1)$ has signs $(-, +, +)$ — octant II.
  3. $(1, -1, -1)$ has signs $(+, -, -)$ — octant VIII.
  4. $(-1, -1, -1)$ has signs $(-, -, -)$ — octant VII.

Answer: Octants I, II, VIII and VII — four different octants are represented.

10
Worked Example
A cuboid has one vertex at the origin and edges of lengths $3$, $4$ and $5$ along the positive $x$-, $y$- and $z$-axes. Write the coordinates of all eight vertices.
Solution
  1. Each vertex takes an $x$ from $\{0, 3\}$, a $y$ from $\{0, 4\}$ and a $z$ from $\{0, 5\}$.
  2. The two faces with $z = 0$: $(0,0,0),\ (3,0,0),\ (0,4,0),\ (3,4,0)$.
  3. The two faces with $z = 5$: $(0,0,5),\ (3,0,5),\ (0,4,5),\ (3,4,5)$.
  4. That is $2 \times 2 \times 2 = 8$ vertices, all in the first octant or on its bounding planes.

Answer: The vertices are $(0,0,0),\ (3,0,0),\ (0,4,0),\ (3,4,0),\ (0,0,5),\ (3,0,5),\ (0,4,5),\ (3,4,5)$.

11
Worked Example
Reflect $A(-2, 5, -3)$ in (a) the origin, (b) the $YZ$-plane.
Solution
  1. (a) Reflection in the origin reverses all three signs: $(2, -5, 3)$.
  2. (b) Reflection in the $YZ$-plane ($x = 0$) reverses only the $x$-coordinate: $(2, 5, -3)$.

Answer: (a) $(2, -5, 3)$; (b) $(2, 5, -3)$.

Key Points

  • A point in space needs an ordered triple $(x, y, z)$; the three mutually perpendicular axes meet at the origin $O(0,0,0)$, drawn by the right-hand rule.
  • The three coordinate planes are $XY$ ($z=0$), $YZ$ ($x=0$) and $ZX$ ($y=0$).
  • $x$, $y$, $z$ are the perpendicular distances of $P$ from the $YZ$-, $ZX$- and $XY$-planes respectively, taken with sign.
  • One zero coordinate places a point on a coordinate plane; two zeros place it on an axis; three zeros give the origin.
  • The three planes cut space into 8 octants; octant I is $(+,+,+)$, and octants I–IV lie above the $XY$-plane ($z>0$), V–VIII below it ($z<0$).
  • Reflections: in the $XY$-plane flip $z$; in the $YZ$-plane flip $x$; in the $ZX$-plane flip $y$; in the origin flip all three.
Tap an option to check your answer0 / 4
Q1.The number of octants in space is:
Explanation: Three coordinate planes divide space into $8$ octants.
Q2.The coordinates of the origin are:
Explanation: All three coordinates are zero.
Q3.On the $xy$-plane, the $z$-coordinate is:
Explanation: Points on the $xy$-plane have $z=0$.
Q4.The point $(1,2,3)$ lies in the:
Explanation: All coordinates positive $\Rightarrow$ first octant.