Vidaara.orgClass 12 · Mathematics
CodeVID-M12-04-DET-01
Determinants & Properties — Assignment
Name: ____________________
Roll No.: __________
Date: ____________
General Instructions
- All questions are compulsory.
- Section A carries 1 mark each, Section B 2 marks, Section C 3 marks and Section D 5 marks.
- Show all working for Sections B, C and D. Only final answers are given at the end — for full solutions, raise your doubts with your teacher.
Section A — Multiple Choice Questions
5 × 1 = 5 marks
1.
$\begin{vmatrix}5&2\\3&1\end{vmatrix}=$
- A.$-1$
- B.$1$
- C.$11$
- D.$13$
2.
If $|A|=4$ for a $3\times3$ matrix, then $|2A|=$
- A.$8$
- B.$12$
- C.$32$
- D.$64$
3.
A determinant with two identical rows equals:
- A.$1$
- B.$0$
- C.the row
- D.$-1$
4.
$|AB|=$
- A.$|A|+|B|$
- B.$|A||B|$
- C.$|A|-|B|$
- D.$|A^{T}|$
5.
$|A^{T}|=$
- A.$|A|$
- B.$-|A|$
- C.$\tfrac{1}{|A|}$
- D.$0$
Section B — Short Answer (2 marks)
4 × 2 = 8 marks
6.
Evaluate $\begin{vmatrix}2&4\\1&3\end{vmatrix}$.
7.
If $|A|=3$ for a $3\times3$ matrix, find $|3A|$.
8.
Evaluate $\begin{vmatrix}1&2&3\\0&1&4\\0&0&5\end{vmatrix}$.
9.
Without expanding, write the value of $\begin{vmatrix}1&1\\2&2\end{vmatrix}$.
Section C — Short Answer (3 marks)
4 × 3 = 12 marks
10.
Find $x$ if $\begin{vmatrix}x&2\\3&x\end{vmatrix}=0$.
11.
Evaluate $\begin{vmatrix}2&-1&0\\1&3&2\\0&1&1\end{vmatrix}$.
12.
If $A$ is $3\times3$ with $|A|=2$, find $|A^{-1}|$.
13.
Solve $\begin{vmatrix}x&1\\4&2\end{vmatrix}=0$ for $x$.
Section D — Long Answer (5 marks)
2 × 5 = 10 marks
14.
Find the area of the triangle with vertices $(1,0),(0,1),(0,0)$ using determinants.
15.
Prove that $\begin{vmatrix}1&a&a^2\\1&b&b^2\\1&c&c^2\end{vmatrix}=(a-b)(b-c)(c-a)$.
Answer Key
Section A — Multiple Choice Questions
- (A) $-1$
- (C) $32$
- (B) $0$
- (B) $|A||B|$
- (A) $|A|$
Section B — Short Answer (2 marks)
- $2$.
- $81$.
- $5$.
- $0$.
Section C — Short Answer (3 marks)
- $x=\pm\sqrt6$.
- $3$.
- $\tfrac12$.
- $x=2$.
Section D — Long Answer (5 marks)
- $\tfrac12$ square unit.
- $=(a-b)(b-c)(c-a)$.
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