Vidaara.orgClass 7 · Mathematics
CodeVID-M07-10-BPR-01
Basic Probability - Assignment
Name: ____________________
Roll No.: __________
Date: ____________
General Instructions
- All questions are compulsory.
- Section A carries 1 mark each, Section B 2 marks, Section C 3 marks and Section D 5 marks.
- Show all working for Sections B, C and D. Only final answers are given at the end — for full solutions, raise your doubts with your teacher.
Section A — Multiple Choice Questions
5 × 1 = 5 marks
1.
A probability lies between:
- A.$-1$ and $1$
- B.$0$ and $1$
- C.$0$ and $10$
- D.$1$ and $2$
2.
A certain event has probability:
- A.$0$
- B.$0.5$
- C.$1$
- D.$2$
3.
An impossible event has probability:
- A.$0$
- B.$0.5$
- C.$1$
- D.$-1$
4.
$P(\text{head})$ on a fair coin is:
- A.$0$
- B.$\tfrac12$
- C.$1$
- D.$\tfrac14$
5.
$P=$
- A.$\tfrac{\text{favourable}}{\text{total}}$
- B.$\tfrac{\text{total}}{\text{favourable}}$
- C.favourable
- D.total
Section B — Short Answer (2 marks)
4 × 2 = 8 marks
6.
Find $P(\text{head})$ on a fair coin.
7.
Find $P(\text{a }4)$ on a die.
8.
Find $P(\text{certain event})$.
9.
Find $P(\text{impossible event})$.
Section C — Short Answer (3 marks)
4 × 3 = 12 marks
10.
Find $P(\text{an even number})$ on a die.
11.
Find $P(\text{a number} > 4)$ on a die.
12.
A bag has $3$ red and $5$ blue balls. Find $P(\text{red})$.
13.
If $P(\text{rain})=0.6$, find $P(\text{no rain})$.
Section D — Long Answer (5 marks)
2 × 5 = 10 marks
14.
A bag has $4$ red, $5$ green and $6$ yellow balls. Find $P(\text{red})$, $P(\text{green})$ and $P(\text{not yellow})$.
15.
A number is chosen from $1$ to $12$. Find $P(\text{a multiple of }3)$ and $P(\text{a prime})$.
Answer Key
Section A — Multiple Choice Questions
- (B) $0$ and $1$
- (C) $1$
- (A) $0$
- (B) $\tfrac12$
- (A) $\tfrac{\text{favourable}}{\text{total}}$
Section B — Short Answer (2 marks)
- $\tfrac12$.
- $\tfrac16$.
- $1$.
- $0$.
Section C — Short Answer (3 marks)
- $\tfrac12$.
- $\tfrac13$.
- $\tfrac38$.
- $0.4$.
Section D — Long Answer (5 marks)
- $\tfrac{4}{15}$, $\tfrac13$, $\tfrac35$.
- $\tfrac13$ and $\tfrac{5}{12}$.
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