Vidaara.orgClass 8 · Mathematics
CodeVID-M08-07-GP-01
Geometric Progressions - Assignment
Name: ____________________
Roll No.: __________
Date: ____________
General Instructions
- All questions are compulsory.
- Section A carries 1 mark each, Section B 2 marks, Section C 3 marks and Section D 5 marks.
- Show all working for Sections B, C and D. Only final answers are given at the end — for full solutions, raise your doubts with your teacher.
Section A — Multiple Choice Questions
5 × 1 = 5 marks
1.
In a GP each term is multiplied by a constant:
- A.difference
- B.ratio
- C.sum
- D.square
2.
The $n$-th term of a GP is:
- A.$a+(n-1)d$
- B.$a\,r^{n-1}$
- C.$an$
- D.$a+nr$
3.
For $2, 6, 18$, $r=$
- A.$2$
- B.$3$
- C.$4$
- D.$6$
4.
The first term of $5, 10, 20$ is:
- A.$2$
- B.$5$
- C.$10$
- D.$20$
5.
For $3, 6, 12, 24$, $r=$
- A.$2$
- B.$3$
- C.$4$
- D.$\tfrac12$
Section B — Short Answer (2 marks)
4 × 2 = 8 marks
6.
Find $r$ for $4, 12, 36$.
7.
Find the next term: $2, 6, 18, \ldots$
8.
Find the 4th term of $1, 2, 4, \ldots$
9.
Is $2, 4, 6, 8$ a GP?
Section C — Short Answer (3 marks)
4 × 3 = 12 marks
10.
Find the 5th term of the GP $3, 6, 12, \ldots$
11.
Find the common ratio and 4th term of $2, 10, 50, \ldots$
12.
Find the next two terms: $81, 27, 9, \ldots$
13.
Find the 3rd term of a GP with $a=5,\ r=2$.
Section D — Long Answer (5 marks)
2 × 5 = 10 marks
14.
For the GP $2, 6, 18, 54, \ldots$, find the 6th term.
15.
The 2nd term of a GP is $6$ and the 4th term is $54$. Find the first term and common ratio.
Answer Key
Section A — Multiple Choice Questions
- (B) ratio
- (B) $a\,r^{n-1}$
- (B) $3$
- (B) $5$
- (A) $2$
Section B — Short Answer (2 marks)
- $3$.
- $54$.
- $8$.
- No.
Section C — Short Answer (3 marks)
- $48$.
- $r=5$; 4th term $250$.
- $3,\ 1$.
- $20$.
Section D — Long Answer (5 marks)
- $486$.
- $a=2,\ r=3$.
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