Vidaara.orgClass 8 · Mathematics
CodeVID-M08-07-NUM-01
Number Patterns - Assignment
Name: ____________________
Roll No.: __________
Date: ____________
General Instructions
- All questions are compulsory.
- Section A carries 1 mark each, Section B 2 marks, Section C 3 marks and Section D 5 marks.
- Show all working for Sections B, C and D. Only final answers are given at the end — for full solutions, raise your doubts with your teacher.
Section A — Multiple Choice Questions
5 × 1 = 5 marks
1.
The next term of $2, 4, 6, 8, \ldots$ is:
- A.$9$
- B.$10$
- C.$12$
- D.$16$
2.
$1, 4, 9, 16$ are:
- A.even numbers
- B.perfect squares
- C.primes
- D.cubes
3.
The rule for $5, 10, 15, 20$ is:
- A.add $3$
- B.add $5$
- C.multiply by $2$
- D.add $10$
4.
The next term of $1, 3, 5, 7$ is:
- A.$8$
- B.$9$
- C.$10$
- D.$11$
5.
$1, 8, 27$ are perfect:
- A.squares
- B.cubes
- C.primes
- D.evens
Section B — Short Answer (2 marks)
4 × 2 = 8 marks
6.
Write the next two terms: $3, 6, 9, \ldots$
7.
Write the next term: $1, 4, 9, 16, \ldots$
8.
Find the rule: $2, 6, 18, 54$.
9.
Write the next term: $100, 90, 80, \ldots$
Section C — Short Answer (3 marks)
4 × 3 = 12 marks
10.
Find the next two terms: $1, 1, 2, 3, 5, 8, \ldots$
11.
Find the missing term: $4, 9, \,\rule{1em}{0.4pt}\,, 25, 36$.
12.
Find the rule and next term: $2, 4, 8, 16$.
13.
Write the 6th term of $5, 10, 15, \ldots$
Section D — Long Answer (5 marks)
2 × 5 = 10 marks
14.
For the triangular numbers $1, 3, 6, 10, 15, \ldots$, find the next two terms and state the rule.
15.
For the square numbers $1, 4, 9, 16, \ldots$, find the 7th term and describe the rule.
Answer Key
Section A — Multiple Choice Questions
- (B) $10$
- (B) perfect squares
- (B) add $5$
- (B) $9$
- (B) cubes
Section B — Short Answer (2 marks)
- $12,\ 15$.
- $25$.
- Multiply by $3$.
- $70$.
Section C — Short Answer (3 marks)
- $13,\ 21$ (Fibonacci).
- $16$.
- Multiply by $2$; next $32$.
- $30$.
Section D — Long Answer (5 marks)
- $21,\ 28$; add one more each time (add $6$, then $7$).
- $49$; the $n$-th term is $n^2$.
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