Vidaara.orgClass 9 · Mathematics
CodeVID-M09-12-HER-01
Heron's Formula - Assignment
Name: ____________________
Roll No.: __________
Date: ____________
General Instructions
- All questions are compulsory.
- Section A carries 1 mark each, Section B 2 marks, Section C 3 marks and Section D 5 marks.
- Show all working for Sections B, C and D. Only final answers are given at the end — for full solutions, raise your doubts with your teacher.
Section A — Multiple Choice Questions
5 × 1 = 5 marks
1.
The semi-perimeter $s=$
- A.$a+b+c$
- B.$\tfrac{a+b+c}{2}$
- C.$\tfrac{a+b+c}{3}$
- D.$abc$
2.
Heron's formula: area $=$
- A.$\sqrt{s(s-a)(s-b)(s-c)}$
- B.$\tfrac12 bh$
- C.$s(s-a)$
- D.$abc$
3.
Heron's formula needs the lengths of:
- A.one side
- B.all three sides
- C.the height
- D.two angles
4.
For sides $3,4,5$, $s=$
- A.$6$
- B.$12$
- C.$5$
- D.$7$
5.
The area of a $3,4,5$ triangle is:
- A.$5$
- B.$6$
- C.$12$
- D.$10$
Section B — Short Answer (2 marks)
4 × 2 = 8 marks
6.
Find $s$ for sides $5,6,7$.
7.
Find the area of a triangle with sides $3,4,5$.
8.
State Heron's formula.
9.
Find $s$ for an equilateral triangle of side $6$.
Section C — Short Answer (3 marks)
4 × 3 = 12 marks
10.
Find the area of a triangle with sides $7,8,9$.
11.
Find the area of a triangle with sides $5,12,13$.
12.
Find the area of an equilateral triangle of side $6$ using Heron's formula.
13.
Find the area of a triangle with sides $6,8,10$.
Section D — Long Answer (5 marks)
2 × 5 = 10 marks
14.
Find the area of a triangle with sides $13$ cm, $14$ cm and $15$ cm using Heron's formula.
15.
A triangular park has sides $40$ m, $24$ m and $32$ m. Find its area and the cost of levelling at $\textsf{Rs }5$ per m$^2$.
Answer Key
Section A — Multiple Choice Questions
- (B) $\tfrac{a+b+c}{2}$
- (A) $\sqrt{s(s-a)(s-b)(s-c)}$
- (B) all three sides
- (A) $6$
- (B) $6$
Section B — Short Answer (2 marks)
- $9$.
- $6$.
- Area $=\sqrt{s(s-a)(s-b)(s-c)}$.
- $9$.
Section C — Short Answer (3 marks)
- $12\sqrt5$.
- $30$.
- $9\sqrt3$.
- $24$.
Section D — Long Answer (5 marks)
- $84$ cm$^2$.
- Area $384$ m$^2$; cost $\textsf{Rs }1920$.
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