Vidaara.orgClass 9 · Mathematics
CodeVID-M09-23-CNV-01
Converse of Pythagoras - Assignment
Name: ____________________
Roll No.: __________
Date: ____________
General Instructions
- All questions are compulsory.
- Section A carries 1 mark each, Section B 2 marks, Section C 3 marks and Section D 5 marks.
- Show all working for Sections B, C and D. Only final answers are given at the end — for full solutions, raise your doubts with your teacher.
Section A — Multiple Choice Questions
5 × 1 = 5 marks
1.
If $a^2+b^2=c^2$, the angle opposite $c$ is:
- A.$60^\circ$
- B.$90^\circ$
- C.$45^\circ$
- D.$120^\circ$
2.
The converse tests whether a triangle is:
- A.equilateral
- B.right-angled
- C.isosceles
- D.scalene
3.
For $6,8,10$, the triangle is:
- A.acute
- B.obtuse
- C.right-angled
- D.not a triangle
4.
The largest side is taken as the:
- A.base
- B.height
- C.hypotenuse $c$
- D.median
5.
If $a^2+b^2
A.right-angled B.acute C.obtuse D.equilateral
Section B — Short Answer (2 marks)
4 × 2 = 8 marks
6.
Is $5,12,13$ a right triangle?
7.
Is $4,5,6$ a right triangle?
8.
State the converse of Pythagoras' theorem.
9.
Is $9,12,15$ right-angled?
Section C — Short Answer (3 marks)
4 × 3 = 12 marks
10.
Check whether $7,24,25$ form a right triangle.
11.
Check whether $8,15,17$ form a right triangle.
12.
Check whether $10,24,26$ form a right triangle.
13.
Is $5,6,8$ right, acute or obtuse?
Section D — Long Answer (5 marks)
2 × 5 = 10 marks
14.
Determine whether the triangle with sides $9,40,41$ is right-angled, and name the hypotenuse.
15.
The sides of a triangle are $11,60,61$. Show whether it is right-angled.
Answer Key
Section A — Multiple Choice Questions
- (B) $90^\circ$
- (B) right-angled
- (C) right-angled
- (C) hypotenuse $c$
- (C) obtuse
Section B — Short Answer (2 marks)
- Yes.
- No ($16+25\ne36$).
- If $a^2+b^2=c^2$, the triangle is right-angled.
- Yes.
Section C — Short Answer (3 marks)
- Yes ($49+576=625$).
- Yes.
- Yes ($100+576=676$).
- Obtuse ($25+36<64$).
Section D — Long Answer (5 marks)
- Right-angled; hypotenuse $41$ ($81+1600=1681$).
- Yes; $121+3600=3721=61^2$.
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