NEET (UG)

Principles of Inheritance and Variation

Mendel's laws, monohybrid and dihybrid crosses, incomplete dominance and codominance, the chromosomal theory, linkage, sex determination, mutation and genetic disorders

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Module 1

Mendelian Inheritance and Its Extensions

Mendel's Experiments and the Monohybrid CrossTopic 1

Genetics is the study of inheritance and variation, and its foundations were laid by Gregor Mendel, who worked on the garden pea (Pisum sativum). The pea was an excellent choice: it has several clear contrasting traits (he studied seven, such as tall/dwarf and round/wrinkled seeds), it is naturally self-pollinating (so true-breeding lines are easy to keep), it has a short life cycle and produces many offspring for statistical analysis.

In a monohybrid cross Mendel crossed two true-breeding parents differing in one trait, e.g. tall (TT) × dwarf (tt). The whole F1 generation was tall (Tt) — the dwarf character had not blended or disappeared but was simply masked. This is the Law of Dominance: in a hybrid, one allele (the dominant, T) expresses itself and the other (the recessive, t) stays hidden.

When the F1 plants were self-pollinated, the F2 generation showed both tall and dwarf plants in a 3:1 phenotypic ratio (and a 1:2:1 genotypic ratio: 1 TT : 2 Tt : 1 tt). The dwarf trait reappeared, proving that the recessive allele had been present but hidden in the F1. To explain this Mendel proposed the Law of Segregation (Law of Purity of Gametes): the two alleles of a trait separate during gamete formation, so each gamete carries only one allele; a gamete is therefore always 'pure' for the trait.

To find the genotype of a tall plant (TT or Tt?), Mendel used a test cross — crossing the unknown with the homozygous recessive (tt). If the tall plant is TT, all offspring are tall; if it is Tt, the offspring are 1 tall : 1 dwarf (1:1). For NEET, fix why the pea was chosen, the monohybrid F2 ratios (3:1 phenotype, 1:2:1 genotype), the Laws of Dominance and Segregation, and the test-cross logic (1:1 reveals a heterozygote).

Figure — Mendel's Experiments and the Monohybrid Cross
ConceptDetail
Materialgarden pea (Pisum sativum), 7 traits
Monohybrid F2 phenotype3 : 1
Monohybrid F2 genotype1 (TT) : 2 (Tt) : 1 (tt)
Law of Segregationalleles separate; gametes are pure
Test cross× tt → 1:1 reveals a heterozygote
Worked Examples
1

A tall pea plant is crossed with a dwarf one; the offspring are 1 tall : 1 dwarf. What was the genotype of the tall parent?

Show solution

This is a test cross (the dwarf is tt). A 1:1 ratio shows the tall parent was heterozygous (Tt) — if it had been TT, all offspring would have been tall.

2

State the Law of Segregation and give the F2 genotypic ratio of a monohybrid cross.

Show solution

The Law of Segregation: the two alleles of a character separate during gamete formation, so each gamete receives only one (gametes are pure). The F2 genotypic ratio is 1 TT : 2 Tt : 1 tt (1:2:1).

✎ Self-Check — 5 questions0 / 5
Q1.

Mendel worked on the:

Explanation: Mendel used the garden pea, Pisum sativum.
Q2.

The F2 phenotypic ratio of a monohybrid cross is:

Explanation: Monohybrid F2 phenotype = 3:1.
Q3.

The genotypic ratio of a monohybrid F2 is:

Explanation: Genotypic ratio = 1 TT : 2 Tt : 1 tt.
Q4.

The law of purity of gametes is another name for the Law of:

Explanation: The Law of Segregation = law of purity of gametes.
Q5.

A test cross is made with a:

Explanation: Test cross uses the homozygous recessive to reveal the genotype.

NEET tip: Pea = clear traits, self-pollinating, short cycle, many offspring. Monohybrid F2: 3:1 phenotype, 1:2:1 genotype. Law of Dominance + Law of Segregation (purity of gametes). Test cross × tt: 1:1 = heterozygote, all dominant = homozygous.

Dihybrid Cross and Extensions of MendelismTopic 2

In a dihybrid cross Mendel followed two traits at once, e.g. round-yellow (RRYY) × wrinkled-green (rryy). The F1 were all round-yellow (RrYy). On selfing, the F2 showed four phenotypes in the famous 9:3:3:1 ratio (9 round-yellow : 3 round-green : 3 wrinkled-yellow : 1 wrinkled-green). The appearance of the two new combinations (round-green and wrinkled-yellow) showed that the two traits were inherited independently. This is the Law of Independent Assortment: during gamete formation, the alleles of one trait assort independently of the alleles of another.

Later work showed that not all inheritance follows simple dominance — these are the extensions of Mendelism. In incomplete dominance, the heterozygote shows a blended, intermediate phenotype. The classic example is the snapdragon (Antirrhinum) or 4-o'clock plant: red (RR) × white (rr) gives pink (Rr) in F1, and the F2 ratio is 1 red : 2 pink : 1 white — i.e. the phenotypic ratio equals the genotypic ratio (1:2:1) because each genotype looks different.

In codominance, both alleles are fully and equally expressed in the heterozygote, so both characters appear together (not blended). The best example is the human ABO blood group: a person with genotype I^A I^B has blood group AB, showing both A and B antigens.

The ABO system also illustrates multiple alleles — a gene with more than two alleles in the population. Here three alleles exist: I^A and I^B (codominant to each other, both dominant over i) and i (recessive), giving blood groups A, B, AB and O. Another extension is pleiotropy, where a single gene affects several traits (e.g. phenylketonuria, sickle-cell anaemia). For NEET, fix the dihybrid 9:3:3:1 and Independent Assortment, and clearly separate incomplete dominance (blended; pink; F2 1:2:1) from codominance (both expressed; AB blood) and multiple alleles (I^A, I^B, i).

Figure — Dihybrid Cross and Extensions of Mendelism
ConceptExample / ratio
Dihybrid F29 : 3 : 3 : 1 (Independent Assortment)
Incomplete dominancesnapdragon: Rr = pink; F2 1:2:1
CodominanceAB blood group (both A & B expressed)
Multiple allelesABO: I^A, I^B, i
Pleiotropyone gene → many traits (PKU, sickle-cell)
Worked Examples
1

In snapdragon, why does the F2 of a red × white cross show a 1:2:1 ratio for both phenotype and genotype?

Show solution

Because this is incomplete dominance: the heterozygote (Rr) is pink — distinct from both red (RR) and white (rr). Since every genotype has its own appearance, the phenotypic ratio (1 red : 2 pink : 1 white) equals the genotypic ratio (1:2:1).

2

Why is the AB blood group an example of codominance, and which alleles control the ABO system?

Show solution

In group AB (I^A I^B), both the A and B antigens are expressed equally — neither masks the other — which is codominance. The ABO system is governed by three alleles (multiple alleles): I^A, I^B and i.

✎ Self-Check — 5 questions0 / 5
Q1.

The F2 phenotypic ratio of a dihybrid cross is:

Explanation: Dihybrid F2 = 9:3:3:1.
Q2.

Pink-flowered snapdragons (Rr) are an example of:

Explanation: The blended pink colour shows incomplete dominance.
Q3.

The AB blood group illustrates:

Explanation: Both A and B antigens are expressed — codominance.
Q4.

The ABO blood group is controlled by:

Explanation: Three alleles: I^A, I^B and i.
Q5.

A single gene affecting several traits shows:

Explanation: Pleiotropy = one gene, many phenotypic effects.

NEET tip: Dihybrid F2 = 9:3:3:1 → Law of Independent Assortment. Incomplete dominance = blended (snapdragon Rr pink; F2 1:2:1). Codominance = both expressed (AB blood). ABO = multiple alleles (I^A, I^B, i). Pleiotropy = one gene → many traits.

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Module 2

Chromosomal Inheritance, Sex Determination and Disorders

Chromosomal Theory, Linkage and Sex DeterminationTopic 3

Mendel's 'factors' were later identified with genes on chromosomes. The chromosomal theory of inheritance, proposed by Sutton and Boveri, noted that the behaviour of chromosomes during meiosis (pairing, segregation and independent assortment) exactly parallels Mendel's laws — so genes must be located on chromosomes.

If genes are on chromosomes, then genes on the same chromosome should be inherited together. This is linkage, discovered by Thomas Hunt Morgan working on the fruit fly Drosophila melanogaster. Linked genes do not assort independently; instead they tend to stay together. The strength of linkage depends on the distance between the genes: genes that are close together are tightly linked (rarely separated), while genes far apart are separated more often by recombination (crossing over). Morgan's student Sturtevant used recombination frequency to build the first genetic maps of chromosomes.

Whether an organism is male or female is fixed by sex determination, which often involves special sex chromosomes. In the XX–XY type (humans and Drosophila), the female is XX and the male is XY; here the male is heterogametic (makes X- and Y-bearing gametes). In the XX–XO type (some insects like grasshoppers), females are XX and males have a single X (XO). In the ZZ–ZW type (birds), the situation is reversed — the female is heterogametic (ZW) and the male is ZZ.

In humans, each cell has 23 pairs of chromosomes — 22 pairs of autosomes plus one pair of sex chromosomes (XX in females, XY in males). Because the female always contributes an X but the male contributes either an X or a Y, it is the father's sperm that determines the sex of the child. For NEET, fix Sutton & Boveri (chromosomal theory), Morgan's linkage/recombination on Drosophila, and the sex-determination systems with which sex is heterogametic in each.

Figure — Chromosomal Theory, Linkage and Sex Determination
ConceptDetail
Chromosomal theorySutton & Boveri — genes on chromosomes
LinkageMorgan, Drosophila; genes on same chromosome
XX–XYhumans/Drosophila; male heterogametic
ZZ–ZWbirds; female heterogametic
Human chromosomes22 autosome pairs + XX/XY
Worked Examples
1

Why are two genes located far apart on the same chromosome more likely to be separated than two genes close together?

Show solution

Genes that are far apart have more chromosomal length between them where crossing over (recombination) can occur, so they are separated more often (loosely linked). Genes that are close together are rarely separated (tightly linked).

2

Which sex is heterogametic in (i) humans and (ii) birds?

Show solution

(i) In humans (XX–XY), the male is heterogametic (XY — makes X and Y gametes). (ii) In birds (ZZ–ZW), the female is heterogametic (ZW).

✎ Self-Check — 5 questions0 / 5
Q1.

The chromosomal theory of inheritance was proposed by:

Explanation: Sutton and Boveri linked Mendel's laws to chromosome behaviour.
Q2.

Linkage was discovered by Morgan working on:

Explanation: Morgan studied linkage in Drosophila.
Q3.

In humans the male is:

Explanation: Human males are XY — heterogametic.
Q4.

In birds, the heterogametic sex is the:

Explanation: Birds use ZZ–ZW; the female (ZW) is heterogametic.
Q5.

The number of autosome pairs in humans is:

Explanation: 22 pairs of autosomes + 1 pair of sex chromosomes.

NEET tip: Sutton & Boveri = chromosomal theory. Morgan = linkage/recombination (Drosophila); closer genes = tighter linkage. Sex determination: XX–XY (humans, male heterogametic), XX–XO (insects), ZZ–ZW (birds, female heterogametic). Humans: 22 autosome pairs + XX/XY; father's sperm decides sex.

Mutation and Genetic DisordersTopic 4

Variation can also arise suddenly through mutation — a change in the genetic material (DNA). A point (gene) mutation changes a single base pair; the classic example is sickle-cell anaemia, caused by the substitution of a single base that changes one amino acid (glutamic acid → valine, Glu→Val) at the sixth position of the haemoglobin β-chain. A frameshift mutation (insertion or deletion of bases) shifts the reading frame and alters everything downstream. Mutations are the raw material of variation and evolution but can also cause disease.

Human genetic disorders are of two broad kinds. Mendelian disorders are caused by an alteration in a single gene and follow Mendelian inheritance. Important X-linked recessive disorders are haemophilia (blood fails to clot) and colour blindness (red-green) — both are far more common in males, who need only one defective X. Important autosomal recessive disorders include sickle-cell anaemia and thalassaemia (defective haemoglobin) and phenylketonuria (PKU) (a metabolic disorder where phenylalanine cannot be broken down). Thalassaemia is a quantitative problem (too little globin made), whereas sickle-cell is a qualitative one (abnormal globin).

Chromosomal disorders are caused by the absence, excess or abnormal arrangement of chromosomes, usually due to non-disjunction (failure of chromosomes to separate in meiosis). Down's syndrome is a trisomy of chromosome 21 (an extra 21), with characteristic features and intellectual disability. Klinefelter's syndrome is 47, XXY — an individual who is overall male but with some feminine features and usually sterile. Turner's syndrome is 45, X0 (one X missing) — a female who is sterile with underdeveloped ovaries.

So mutations underlie variation, single-gene changes cause Mendelian disorders, and changes in chromosome number cause chromosomal disorders. For NEET, fix the sickle-cell point mutation (Glu→Val, single base), the inheritance pattern of each Mendelian disorder (haemophilia & colour blindness = X-linked recessive; sickle-cell, thalassaemia, PKU = autosomal recessive), and the three chromosomal disorders with their karyotypes (Down's = trisomy 21; Klinefelter's = XXY; Turner's = X0).

Figure — Mutation and Genetic Disorders
DisorderCause / type
Sickle-cell anaemiapoint mutation (Glu→Val); autosomal recessive
Haemophilia / colour blindnessX-linked recessive (commoner in males)
Thalassaemia / PKUautosomal recessive
Down's syndrometrisomy of chromosome 21
Klinefelter's / Turner's47,XXY (male) / 45,X0 (female)
Worked Examples
1

What is the molecular cause of sickle-cell anaemia?

Show solution

A single base substitution (point mutation) in the gene for the haemoglobin β-chain changes the codon GAG to GUG, replacing glutamic acid with valine (Glu→Val) at the 6th position. This makes the abnormal haemoglobin (HbS) that distorts red cells into a sickle shape. It is autosomal recessive.

2

Give the chromosome basis of (i) Down's syndrome and (ii) Turner's syndrome.

Show solution

(i) Down's syndrome = an extra chromosome 21 (trisomy 21). (ii) Turner's syndrome = 45, X0 — a female with only one X chromosome (one sex chromosome missing).

✎ Self-Check — 5 questions0 / 5
Q1.

Sickle-cell anaemia is caused by the substitution of:

Explanation: Glu→Val at position 6 of the β-globin chain.
Q2.

Haemophilia is a/an:

Explanation: Haemophilia is X-linked recessive (commoner in males).
Q3.

Down's syndrome is due to:

Explanation: An extra chromosome 21 (trisomy 21).
Q4.

Klinefelter's syndrome has the karyotype:

Explanation: Klinefelter's = 47, XXY (a male).
Q5.

Phenylketonuria is a/an:

Explanation: PKU is an autosomal recessive metabolic disorder.

NEET tip: Sickle-cell = point mutation Glu→Val (autosomal recessive). X-linked recessive: haemophilia, colour blindness (commoner in males). Autosomal recessive: sickle-cell, thalassaemia, PKU. Chromosomal (non-disjunction): Down's = trisomy 21; Klinefelter's = 47,XXY (male); Turner's = 45,X0 (female).

Quick Revision — Principles of Inheritance and Variation

  • Mendel (garden pea, 7 traits): Law of Dominance, Law of Segregation (purity of gametes), Law of Independent Assortment.
  • Monohybrid F2 = 3:1 phenotype, 1:2:1 genotype; test cross = 1:1. Dihybrid F2 = 9:3:3:1.
  • Incomplete dominance (snapdragon: Rr = pink; F2 1:2:1) and codominance (AB blood group). ABO = multiple alleles (I^A, I^B, i).
  • Chromosomal theory (Sutton & Boveri); linkage & recombination (Morgan, Drosophila).
  • Sex determination: XX–XY (humans, male heterogametic), ZZ–ZW (birds, female heterogametic), XX–XO (some insects).
  • Mutation: change in DNA (sickle-cell = single base, Glu→Val).
  • Disorders: Mendelian — haemophilia & colour blindness (X-linked), sickle-cell & thalassaemia & PKU (autosomal recessive); chromosomal — Down's (trisomy 21), Klinefelter's (XXY), Turner's (XO).

Frequently Asked Questions

Why did Mendel choose the garden pea, and what are his three laws?
The garden pea (Pisum sativum) was ideal because it has clear contrasting traits, is self-pollinating (so true-breeding lines are easy), has a short life cycle and gives many offspring. From his crosses Mendel proposed three laws: the Law of Dominance (one allele masks the other in a hybrid), the Law of Segregation (the two alleles of a trait separate during gamete formation so each gamete gets only one — the law of purity of gametes), and the Law of Independent Assortment (alleles of different traits are inherited independently).
What ratios are obtained in a monohybrid and a dihybrid cross?
A monohybrid cross (one trait) gives an F2 phenotypic ratio of 3:1 and a genotypic ratio of 1:2:1. A dihybrid cross (two traits) gives an F2 phenotypic ratio of 9:3:3:1. A test cross of a heterozygote with a homozygous recessive gives 1:1.
How does incomplete dominance differ from codominance?
In incomplete dominance the heterozygote shows a blended, intermediate phenotype — e.g. red (RR) × white (rr) snapdragon gives pink (Rr). In codominance both alleles are fully and equally expressed together, so both appear in the heterozygote — e.g. in the AB blood group both A and B antigens are present. In incomplete dominance neither allele dominates; in codominance both express at once.
How is sex determined in humans?
Humans have 22 pairs of autosomes plus one pair of sex chromosomes. Females are XX and males are XY, so the male is heterogametic — he makes two kinds of sperm (X-bearing and Y-bearing) while the female makes only X-bearing eggs. An X sperm gives a girl (XX) and a Y sperm gives a boy (XY); the father's sperm therefore determines the sex of the child.
Give examples of Mendelian and chromosomal genetic disorders.
Mendelian (single-gene) disorders include haemophilia and colour blindness (X-linked recessive), and sickle-cell anaemia, thalassaemia and phenylketonuria (autosomal recessive). Chromosomal disorders are due to extra or missing chromosomes: Down's syndrome (trisomy of chromosome 21), Klinefelter's syndrome (47, XXY — a male) and Turner's syndrome (45, X0 — a female).

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