NEET (UG)

Classification of Elements & Periodicity in Properties

Modern periodic table, blocks, and periodic trends for NEET

1
Module 1

The Modern Periodic Table and Electronic Basis

Development of the Periodic Table and the Modern Periodic LawTopic 1

Long before the modern table, chemists tried to bring order to the elements. Dobereiner grouped elements into triads, where the middle element's atomic mass was roughly the average of the other two. Newlands' law of octaves noticed that every eighth element repeated properties, like musical notes — but it failed beyond calcium. These early attempts are popular one-mark NEET recall points, so it helps to link each name to its one key idea.

Mendeleev made the real breakthrough, arranging elements by increasing atomic mass into his periodic table. His genius lay in leaving gaps for undiscovered elements (such as eka-silicon, later germanium) and even correcting some atomic masses. However, a few pairs (like argon and potassium) appeared out of order, hinting that atomic mass was not the true basis.

The puzzle was solved by Moseley, who showed from X-ray studies that the fundamental property of an element is its atomic number (number of protons), not its mass. This gave the modern periodic law: the properties of elements are a periodic function of their atomic numbers. Reordering by atomic number removed Mendeleev's anomalies at a stroke.

The result is the long form (modern) periodic table of 7 horizontal periods and 18 vertical groups. Elements in the same group have similar valence-shell configurations and hence similar chemistry, while properties change steadily across a period. Understanding that the whole table flows from electronic configuration — not from memorised lists — is the mindset NEET rewards.

Figure — Development of the Periodic Table and the Modern Periodic Law
ContributorKey idea
Dobereinertriads (middle mass = average)
Newlandslaw of octaves
Mendeleevby atomic mass; left gaps
Moseleymodern law (atomic number)
Worked Examples
1

Why did argon ($\text{Ar}$) and potassium ($\text{K}$) appear in the wrong order in Mendeleev's table but the correct order in the modern table?

Show solution

By atomic mass, $\text{Ar}\ (40)$ exceeds $\text{K}\ (39)$, placing them awkwardly. By atomic number, $\text{Ar}\ (18)$ comes before $\text{K}\ (19)$, which matches their properties — confirming atomic number as the correct basis.

2

State the modern periodic law.

Show solution

The properties of elements are a periodic function of their atomic numbers. (Mendeleev's earlier version used atomic mass.)

✎ Self-Check — 5 questions0 / 5
Q1.

The modern periodic law is based on:

Explanation: Properties are a periodic function of atomic number.
Q2.

The law of octaves was proposed by:

Explanation: Newlands' law of octaves.
Q3.

Mendeleev's table left gaps for:

Explanation: He predicted elements like eka-silicon (germanium).
Q4.

The modern periodic table has how many groups?

Explanation: 18 groups and 7 periods.
Q5.

Elements in the same group have similar:

Explanation: Same valence configuration gives similar chemistry.

NEET trap: Mendeleev used atomic mass; the modern law uses atomic number (Moseley). Tie each early chemist to one idea — Dobereiner (triads), Newlands (octaves).

Electronic Configuration, Blocks, Periods and GroupsTopic 2

The shape of the periodic table is a direct map of electronic configuration. The table is divided into four blocks according to which subshell receives the last electron. The s-block (groups 1 and 2) has its last electron in an $s$ orbital; the p-block (groups 13–18) in a $p$ orbital; the d-block (groups 3–12, the transition elements) in a $d$ orbital; and the f-block (lanthanoids and actinoids) in an $f$ orbital. NEET frequently asks you to identify an element's block from its configuration.

Reading position from configuration is a key skill. The period number equals the highest principal quantum number $n$ in the configuration. For the group number: for s-block elements it equals the number of valence $s$ electrons; for p-block elements it is $10 +$ (valence $s + p$ electrons); and for d-block elements it equals the number of $(n-1)d + ns$ electrons. Practising this prediction makes most placement questions automatic.

The blocks correlate with broad chemical character. The s-block holds reactive metals (alkali and alkaline-earth) that readily lose electrons; the p-block spans metals, metalloids and the most important non-metals, including the halogens and noble gases. The d-block transition metals show variable oxidation states and form coloured compounds, while the f-block inner-transition elements are chemically similar within each series.

The noble gases (group 18) sit at the right edge with stable, filled valence shells, which is why they are largely inert. Hydrogen is a special case — placed in group 1 because of its $1s^1$ configuration, yet resembling halogens in some ways. Recognising these block-level patterns helps you predict reactivity and bonding without memorising every element, exactly the efficiency NEET demands.

Figure — Electronic Configuration, Blocks, Periods and Groups
BlockGroups / last electron
s-block1–2; last $e^-$ in $s$
p-block13–18; last $e^-$ in $p$
d-block3–12; last $e^-$ in $d$
f-blocklanthanoids/actinoids; $f$
Worked Examples
1

An element has the configuration $[\text{Ne}]\,3s^2\,3p^3$. Identify its period, group and block.

Show solution

Highest $n = 3$, so period 3. It is a p-block element (last electron in $3p$); group $= 10 + (2 + 3) = 15$. This is phosphorus.

2

To which block does an element with configuration $[\text{Ar}]\,3d^6\,4s^2$ belong?

Show solution

The last electron enters the $3d$ subshell, so it is a d-block (transition) element. (It is iron, $Z = 26$.)

✎ Self-Check — 5 questions0 / 5
Q1.

An element with its last electron in a $d$ orbital belongs to the:

Explanation: Last electron in $d$ to d-block.
Q2.

The period number of an element equals its:

Explanation: Period = highest principal quantum number.
Q3.

Groups 1 and 2 constitute the:

Explanation: s-block elements.
Q4.

The transition elements (groups 3–12) are the:

Explanation: d-block = transition elements.
Q5.

Noble gases belong to group:

Explanation: Group 18, with filled valence shells.

NEET tip: Period = highest $n$. Block = subshell of the last electron. For p-block, group $= 10 + $ (valence $s+p$ electrons). Practise reading position straight from configuration.

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Module 2

Periodic Trends in Properties

Atomic and Ionic RadiiTopic 3

Atomic radius measures the size of an atom, and its variation across the table follows two competing effects: the pull of the nucleus and the screening by inner electrons. Across a period (left to right) the radius decreases, because electrons are added to the same shell while nuclear charge rises, pulling the cloud inward. Down a group the radius increases, because each new period adds a whole new shell that outweighs the greater nuclear charge.

For ions the same logic applies, with a key extra rule. A cation is always smaller than its parent atom: losing electrons (often emptying the outer shell) leaves the same nucleus pulling fewer electrons, so the size shrinks. An anion is always larger than its parent atom: extra electrons increase electron-electron repulsion and expand the cloud. So $\text{Na}^+ < \text{Na}$ and $\text{Cl}^- > \text{Cl}$ — a guaranteed NEET comparison.

A favourite NEET theme is isoelectronic species — ions and atoms with the same number of electrons, such as $\text{N}^{3-}$, $\text{O}^{2-}$, $\text{F}^-$, $\text{Na}^+$, $\text{Mg}^{2+}$ and $\text{Al}^{3+}$ (all with 10 electrons). Among these, size decreases as nuclear charge increases, because more protons pull the same ten electrons more tightly. So the order of size is $\text{N}^{3-} > \text{O}^{2-} > \text{F}^- > \text{Na}^+ > \text{Mg}^{2+} > \text{Al}^{3+}$.

Note that radius is defined differently in different contexts — covalent radius for covalently bonded atoms, van der Waals radius for non-bonded contact, and metallic radius for metals — and van der Waals radius is the largest. For NEET, the reliable working rules are: smaller across a period, larger down a group, cations smaller, anions larger, and more protons mean smaller size for isoelectronic species.

Figure — Atomic and Ionic Radii
ChangeEffect on size
Across a period (→)decreases
Down a group (↓)increases
Cation vs atomsmaller
Anion vs atomlarger
Worked Examples
1

Arrange the isoelectronic species $\text{O}^{2-}$, $\text{F}^-$, $\text{Na}^+$, $\text{Mg}^{2+}$ in decreasing order of size.

Show solution

All have 10 electrons; size decreases as protons increase: $\text{O}^{2-}\,(8\text{p}) > \text{F}^-\,(9\text{p}) > \text{Na}^+\,(11\text{p}) > \text{Mg}^{2+}\,(12\text{p})$.

2

Which is larger, $\text{Na}$ or $\text{Na}^+$, and why?

Show solution

$\text{Na}$ is larger. Forming $\text{Na}^+$ removes the outer $3s$ electron (the whole valence shell), so the cation is considerably smaller than the neutral atom.

✎ Self-Check — 5 questions0 / 5
Q1.

Across a period, atomic radius:

Explanation: Rising nuclear charge on the same shell shrinks the atom.
Q2.

Down a group, atomic radius:

Explanation: New shells increase the size.
Q3.

A cation compared with its parent atom is:

Explanation: Loss of electrons shrinks the species.
Q4.

Among isoelectronic species, size is greatest for the one with the:

Explanation: Fewer protons mean weaker pull, larger size.
Q5.

Which is the largest?

Explanation: $\text{O}^{2-}$ has the fewest protons among these isoelectronic ions.

NEET trap: For isoelectronic species, compare protons: more protons to smaller ion. Cations smaller, anions larger than the parent atom; van der Waals radius is the largest type.

Ionisation Enthalpy, Electron Gain Enthalpy and ElectronegativityTopic 4

Ionisation enthalpy ($\Delta_i H$) is the energy needed to remove the most loosely held electron from a gaseous atom. It increases across a period (electrons held more tightly by greater nuclear charge) and decreases down a group (the outer electron is farther out and well shielded). Successive ionisation enthalpies always rise ($\Delta_i H_1 < \Delta_i H_2 < \dots$) because removing an electron from an increasingly positive ion is progressively harder.

Two famous anomalies are perennial NEET questions. Beryllium has a higher first ionisation enthalpy than boron, because Be's filled $2s^2$ is more stable than B's $2s^2 2p^1$. Nitrogen has a higher value than oxygen, because N's exactly half-filled $2p^3$ is extra stable, so removing an electron from oxygen (which relieves $2p^4$ pairing) is easier. Remembering 'filled and half-filled are stable' explains both.

Electron gain enthalpy ($\Delta_{eg} H$) is the energy change when a gaseous atom gains an electron — usually negative (energy released). It is most negative for the halogens, which are one electron short of a noble-gas shell. A celebrated exception is that chlorine has a more negative value than fluorine: fluorine's small, compact $2p$ shell creates strong repulsion for the incoming electron, so the energy released is less than for the roomier chlorine.

Electronegativity measures an atom's tendency to attract a shared electron pair in a bond. It increases across a period and decreases down a group, making fluorine the most electronegative element. Unlike ionisation and electron gain enthalpies, electronegativity is a relative property (no units, e.g. on the Pauling scale) and depends on the bonding environment. Together, these four trends — radius, ionisation enthalpy, electron gain enthalpy and electronegativity — let you predict metallic/non-metallic character and reactivity, the heart of NEET periodicity questions.

Figure — Ionisation Enthalpy, Electron Gain Enthalpy and Electronegativity
PropertyAcross (→) / Down (↓)
Ionisation enthalpyincreases / decreases
Electron gain enthalpy (magnitude)more negative / less negative
Electronegativityincreases / decreases
Key anomalies$\text{Be}>\text{B}$, $\text{N}>\text{O}$; $\text{Cl}>\text{F}$ (EGE)
Worked Examples
1

Why is the first ionisation enthalpy of nitrogen greater than that of oxygen?

Show solution

Nitrogen has a stable half-filled $2p^3$ configuration that resists electron removal, whereas removing an electron from oxygen's $2p^4$ relieves electron-pair repulsion, so oxygen ionises more easily — giving $\Delta_i H(\text{N}) > \Delta_i H(\text{O})$.

2

Which element is the most electronegative, and where does it sit in the table?

Show solution

Fluorine is the most electronegative element. It lies at the top of group 17, where the combination of small size and high nuclear charge maximises the pull on bonding electrons.

✎ Self-Check — 5 questions0 / 5
Q1.

Ionisation enthalpy generally ___ across a period.

Explanation: Greater nuclear charge holds electrons more tightly.
Q2.

The first ionisation enthalpy of nitrogen is ___ that of oxygen.

Explanation: Half-filled $2p^3$ of N is extra stable.
Q3.

The most negative electron gain enthalpy is shown by:

Explanation: Halogens readily gain an electron.
Q4.

Chlorine has a more negative electron gain enthalpy than fluorine because fluorine is:

Explanation: Small F has high repulsion for the incoming electron.
Q5.

The most electronegative element is:

Explanation: Fluorine has the highest electronegativity.

NEET trap: Memorise the two IE anomalies ($\text{Be}>\text{B}$, $\text{N}>\text{O}$) and the EGE exception ($\text{Cl}>\text{F}$). Electronegativity peaks at fluorine and has no units (relative scale).

Quick Revision — Classification of Elements & Periodicity in Properties

  • Modern periodic law: properties are a periodic function of atomic number (Moseley), not atomic mass.
  • Blocks: last electron enters $s, p, d, f$ to give s-, p-, d-, f-blocks. Groups 1–2 = s; 13–18 = p; 3–12 = d; lanthanoids/actinoids = f.
  • Period number = highest principal quantum number $n$; group follows from valence configuration.
  • Atomic radius: decreases across a period (rising nuclear charge), increases down a group (new shells).
  • Isoelectronic species: same electrons; more protons to smaller size.
  • Ionisation enthalpy: increases across, decreases down. Anomalies: $\text{Be} > \text{B}$ and $\text{N} > \text{O}$ (stable filled/half-filled subshells).
  • Electron gain enthalpy: most negative for halogens; Cl more negative than F (small, compact F).
  • Electronegativity: highest for F; rises across, falls down.
  • Cations are smaller and anions larger than the parent atom.

Frequently Asked Questions

Why is the modern periodic table based on atomic number and not atomic mass?
Moseley showed that the properties of elements depend on the number of protons (atomic number), which fixes the order without the anomalies that arose when Mendeleev used atomic mass.
Why is the ionisation enthalpy of nitrogen higher than that of oxygen?
Nitrogen has a stable exactly half-filled 2p3 configuration, which is harder to disturb, so removing an electron from nitrogen needs more energy than from oxygen.
Why does chlorine have a more negative electron gain enthalpy than fluorine?
Fluorine is very small, so the incoming electron faces strong electron-electron repulsion in its compact 2p shell; chlorine's larger 3p shell accommodates the electron more easily, releasing more energy.
How does atomic size change for isoelectronic species?
Among species with the same number of electrons, the one with the most protons has the greatest nuclear pull and therefore the smallest size.
Are cations smaller or larger than their parent atoms?
Cations are smaller because they have lost electrons (often a whole shell) and the same nucleus now pulls fewer electrons; anions are larger due to added electron-electron repulsion.

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