A 60 W bulb is rated at 220 V — JEE Physics
A 60 W bulb is rated at 220 V. Find the resistance of its filament and current flowing through it.
1 Answer
RRohanIyer58
✓ Accepted
· 26d ago
▲ 40
$$R = \frac{V^2}{P} = \frac{220^2}{60} = \frac{48400}{60} \approx 807\ \Omega$$
$$I = \frac{P}{V} = \frac{60}{220} \approx 0.27 A$$
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Discussion (2)
AK
Is there a faster shortcut for this in the actual exam? Time is tight.
N
Quick doubt: would this method still work if the numbers were not so clean?