[JEE Advanced 2006] $a,b$ are roots of $x^2-10cx-11d=0$ and $c,d$ are roots of $x^2-10ax-11b=0$ ($a\ne b\ne c\ne d$). Find $a+b+c+d$.
$a,b$ are roots of $x^2-10cx-11d=0$ and $c,d$ are roots of $x^2-10ax-11b=0$ ($a\ne b\ne c\ne d$). Find $a+b+c+d$.
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 1mo ago
▲ 0
Answer: $1210$.
$a+b=10c$ and $c+d=10a$ give $a+b+c+d=10(a+c)$. Using the root relations, $(a-c)(a+c-121)=0$, so $a+c=121$ and the sum is $1210$.
JEE Advanced 2006 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.
Log in to post your own answer or join the discussion.
No comments yet — start the discussion.