A bullet of mass 10 g moving at 400 m/s embeds in a stationary block of mass 390 g — JEE Physics
A bullet of mass 10 g moving at 400 m/s embeds in a stationary block of mass 390 g. Find the velocity of the combined system.
1 Answer
SSandeepRanasinghe88
✓ Accepted
· 21d ago
▲ 10
Conservation of momentum:
$$m_1 u_1 = (m_1 + m_2)v$$
$$0.01 \times 400 = (0.01 + 0.39) \times v$$
$$v = \frac{4}{0.4} = 10 m/s$$
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Discussion (2)
SP
How do we know the approximation is valid here?
A
Thanks a ton, I was stuck on this exact problem for an hour.