[JEE Advanced 1989] a five digit number divisible by 3 is formed using 0 1 2 3
A five-digit number divisible by $3$ is formed using $0,1,2,3,4,5$ without repetition. The number of ways is
(a) $216$
(b) $240$
(c) $600$
(d) $3125$
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 2d ago
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Correct answer: (a) $216$
Digit sum $15$; drop a digit $\equiv0\pmod3$ (i.e. $0$ or $3$). Drop $0$: $5!=120$; drop $3$: $5!-4!=96$. Total $216$.
JEE Advanced 1989 · Permutations and Combinations — verified solution by the Vidaara Team.
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